Python 当到达列表的某个元素时停止while循环

我基本上想知道，在这种情况下，当while循环到达列表的某个元素（

“LA Dodgers Stadium”

）时，如何阻止它添加到列表中。在到达列表的该元素后，不应添加任何内容。

此代码似乎工作正常。我打印了PlaceScont的结果，结果是（6,5）。看起来这意味着函数命中了6个单词，其中5个是多单词。这符合你的数据

places= ["Home","In-n Out Burger", "John's house", "Santa Monica Pier", "Staples center",  "LA Dodgers stadium", "Home"]
def placesCount(places):
    multi_word = 0
    count = 0
    while True:
        place = places[count]
        if ' ' in place and place!='LA Dodgers stadium' **""" or anything that comes after LA dogers stadium"""** :
            multi_word += 1
        if '' in place and place!='LA Dodgers stadium' """ **or anything that comes after LA dogers stadium**""":
            count += 1
    print (count, "places to LA dodgers stadium"),  print (multi_word)
placesCount(places)

---

正如Fredrik提到的，使用for-place-in-places循环可以更好地完成您想要做的事情

您的代码似乎正常工作。下面是一个稍微好一点的版本：

place = None
while place != 'stop condition':
    do_stuff()

或使用：

下面是一个如何使用该函数的示例（与原始示例相同，顺便说一句，该函数的行为仍然相同-接受一个位置列表并返回一个包含两个计数的元组）：

---

这不管用吗？用

代替while thingie，用
代替placein places:
在你们的位置上循环；那么您就不需要对空白进行任何特殊处理。还有，为什么不做一个简单的
len（places）
？这可能是OP想要的，+1我如何打印结果？打印（PlaceScont）无效如何打印结果？print（PlaceScont）不起作用如果您的函数返回任何类型的数据（如数字、列表等），您应该可以执行print PlaceScont（PlaceScont）。
def placesCount(places):
    count = 0
    multi_word = 0
    for place in places:
        count += 1
        if ' ' in place:
            multi_word += 1
        if place == 'LA Dodgers stadium':
            break
    return count, multi_word

from itertools import takewhile, ifilter

def placesCount(places):
    # Get list of places up to 'LA Dodgers stadium'
    places = list(takewhile(lambda x: x != 'LA Dodgers stadium', places))

    # And from those get a list of only those that include a space
    multi_places = list(ifilter(lambda x: ' ' in x, places))

    # Return their length
    return len(places), len(multi_places)

places = ["Home","In-n Out Burger", "John's house", "Santa Monica Pier", "Staples center",  "LA Dodgers stadium", "Home"]

# Run the function and save the results
count_all, count_with_spaces = placesCount(places)

# Print out the results
print "There are %d places" % count_all
print "There are %d places with spaces" % count_with_spaces