为python flask中的项目列表分页
我通过以下代码获得python中的项目列表:为python flask中的项目列表分页,python,mongodb,flask,pagination,pymongo,Python,Mongodb,Flask,Pagination,Pymongo,我通过以下代码获得python中的项目列表: from flask_paginate import Pagination @app.route('/retrieve_data') def retrieve(): PER_PAGE=5 connection = MongoClient() db=connection.rheoML fs = gridfs.GridFS(db) search = False q = request.args.get('q
from flask_paginate import Pagination
@app.route('/retrieve_data')
def retrieve():
PER_PAGE=5
connection = MongoClient()
db=connection.rheoML
fs = gridfs.GridFS(db)
search = False
q = request.args.get('q')
if q:
search = True
try:
page = int(request.args.get('page', 2))
except ValueError:
page = 1
List=fs.list()
pagination = Pagination(page=page,per_page=PER_PAGE, total=len(List), search=search, record_name='List')
return render_template("retrieveFile.html",List=List,fs=fs,form="submitIt",pagination=pagination,)
我现在正在学习教程
我还在retrieveFile.html中执行以下操作以适应分页:
<form id="submitIt" name="submitIt" action="/GetFile" method="Post" onsubmit="return validate(this)">
{{ pagination.info }}
<table>
<tr>
<th>Select</th><th>Filename</th><th>Operator</th>
</tr>
{% for file in List %}
<tr>
<td>
<input type="checkbox" name="FileName" value={{file.strip('u').strip("'")}}><br>
</td>
<td>
<name="FileName1" id="file" value={{file.strip('u').strip("'")}}>{{file.strip('u').strip("'")}}<br>
</td>
<td>
{{fs.get_last_version(file).Operator}}<br>
</td>
</tr>
{% endfor %}
</table>
{{ pagination.links }}
<input type="submit" value="Download">
</form>
{{pagination.info}
选择FileNameOperator
{列表%中文件的%s}
{{file.strip('u').strip('“”}}
{{fs.get_last_version(file.Operator}}}
{%endfor%}
{{pagination.links}
我将此添加到我的样式标记中
<style>
.pagination-page-info {
padding: .6em;
padding-left: 0;
width: 40em;
margin: .5em;
margin-left: 0;
font-size: 12px;
}
.pagination-page-info b {
color: black;
background: #6aa6ed;
padding-left: 2px;
padding: .1em .25em;
font-size: 150%;
}
</style>
.分页页面信息{
填充:.6em;
左侧填充:0;
宽度:40em;
边缘:.5em;
左边距:0;
字体大小:12px;
}
.分页页面信息b{
颜色:黑色;
背景:#6aa6ed;
左侧填充:2px;
填充物:1em.25em;
字体大小:150%;
}
问题是,当显示页面时,页码很好,但所有项目都显示在一个页面中。请帮帮我,我还是个分页新手,还在努力解决问题。整理好了吗
只需要编辑
try:
page = int(request.args.get('page', 1))
except ValueError:
page = 1
List=fs.list()
i=(page-1)*PER_PAGE
List1=List[i:i+5]
pagination = Pagination(page=page,per_page=PER_PAGE, total=len(List), search=search, record_name='List')
return render_template("retrieveFile.html",List=List1,fs=fs,form="submitIt",pagination=pagination,)
这里的回答非常晚,但希望这能澄清: 除了捕获页面和每页值外,还需要偏移量来帮助正确显示每页上的结果。实际上,有一个方便的方法可以设置这三个参数,您可以使用flask\u paginate import get\u page\u args中的
导入它们。下面是完整的view.py代码:
from flask_paginate import Pagination, get_page_args
@search.route('/retrieve_data')
def retrieve():
# get_page_arg defaults to page 1, per_page of 10
page, per_page, offset = get_page_args()
# After the main query, you need to apply the per_page limit and offset
fs = gridfs.GridFS(db)
fs_for_render = fs.limit(per_page).offset(offset)
#you can also add css_framework='bootstrap3' to Pagination for easy styling
pagination = Pagination(page=page, per_page=per_page, offset=offset,
total=fs.count(), record_name='List')
return render_template('retrieveFile.html', fs=fs_for_render, pagination=pagination,
form="submitIt")
现在的问题是我得到了Horizontal中的链接这一行极大地帮助了我fs_for_render=fs.limit(per_page).offset(offset)。你是互联网上的英雄。