在python中为列表中的项生成word cloud

我正在使用

 my_list=["one", "one two", "three"]

当我将所有项目转换为字符串时，它正在为其生成单词cloud

 wordcloud = WordCloud(width = 1000, height = 500).generate(" ".join(my_list))

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帮助我为列表中的项目生成word cloud

WordCloud

以正则表达式作为参数。使用此选项，我们可以将拆分字符设置为

+

而不是空格

   "one","two","three"

 But I want to generate word cloud for the values, "one","one two","three"

然后，单词列表需要在

+

上连接，每个单词现在都用于拆分单词。产生以下代码：

regexp=r"\w[\w' ]+"

一种做法是

wordcloud = WordCloud(width=1000, height=500, regexp=r"\w[\w' ]+").generate("+".join(my_list))

另一种方法是创建计数器字典

import matplotlib.pyplot as plt
from wordcloud import WordCloud

#convert list to string and generate
unique_string=(" ").join(my_list)
wordcloud = WordCloud(width = 1000, height = 500).generate(unique_string)
plt.figure(figsize=(15,8))
plt.imshow(wordcloud)
plt.axis("off")
plt.savefig("your_file_name"+".png", bbox_inches='tight')
plt.show()
plt.close()

我得到“keyrerror:”

#convert it to dictionary with values and its occurences
from collections import Counter
word_could_dict=Counter(my_list)
wordcloud = WordCloud(width = 1000, height = 500).generate_from_frequencies(word_could_dict)

plt.figure(figsize=(15,8))
plt.imshow(wordcloud)
plt.axis("off")
#plt.show()
plt.savefig('yourfile.png', bbox_inches='tight')
plt.close()