Python根据字典中的条件查找obj值

我从python请求中获得以下json数据：

{
    "results": [
        {
            "name": "virtual-machine-1",
            "guest": "Microsoft Windows Server 2016 (64-bit)",
            "status": "green",
            "id": "567890-004",
        },
        {
            "name": "virtual-machine-2",
            "guest": "CoreOS Linux (64-bit)",
            "status": "green",
            "id": "567890-005",
        }
    ]
}

如何根据“name”值获取所有字典的“id”值

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我已经看到了在同一个字典中基于键（而不是基于条件）查找值并对多个字典进行迭代的解决方案。感谢您的帮助。

您正在键入id:

>>> {result['id']: result['name'] for result in data['results']}
{'567890-004': 'virtual-machine-1', '567890-005': 'virtual-machine-2'}

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这种技巧被称为字典理解

将json转换为字典列表。那就用速记来表达吧

results = [
{ "name": "virtual-machine-1",
            "guest": "Microsoft Windows Server 2016 (64-bit)",
            "status": "green",
            "id": "567890-004"},
{"name": "virtual-machine-2",
            "guest": "CoreOS Linux (64-bit)",
            "status": "green",
            "id": "567890-005"}
]

id = [x['id'] for x in results if x['name'] == "virtual-machine-1"]
print id    # prints 567890-004

id = [x['id'] for x in results if x['name'] == "virtual-machine-2"]
print id    # prints 567890-005

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什么意思？您是否试图从结果字典中获取“id”的所有值，其中name==some string？仅当结果包含name键时才会返回id，以获取帮助。得到了我所需要的，并且了解了字典的理解。我很难写出一个格式化的评论，因此需要大量的编辑。很抱歉，在查看您的解决方案时，id返回了“[]”，但没有找到匹配项。
例如，上面没有“virtual-machine-3”，如果我尝试使用
id=[x['id']，如果x['name']==“virtual-machine-3”]打印id#打印[]
我预计会出现错误，因为如果我在某处使用“assert id is not None”验证结果，它会为空值返回“True”。

results = [
{ "name": "virtual-machine-1",
            "guest": "Microsoft Windows Server 2016 (64-bit)",
            "status": "green",
            "id": "567890-004"},
{"name": "virtual-machine-2",
            "guest": "CoreOS Linux (64-bit)",
            "status": "green",
            "id": "567890-005"}
]

id = [x['id'] for x in results if x['name'] == "virtual-machine-1"]
print id    # prints 567890-004

id = [x['id'] for x in results if x['name'] == "virtual-machine-2"]
print id    # prints 567890-005