在python中迭代大型文件目录系统，获取太多的值以进行解压缩

我正在用python迭代一个非常大的文件和目录系统。我从基本目录开始，我知道该目录的深度不超过1个文件夹，超过了基本目录。我正在尝试读取base_directories children文件夹中每个文件的第二行，代码如下：

a_list = []
  for dir, files in os.walk(base_directory):
    for file in files:
      f=open(file, 'r')
      for line in f:
        #reads in the second line
        if line==1:
          a_list.append(line)
          break
      f.close() 

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但是我得到了太多的值，无法专门在这行“for dir，file in os.walk（base_directory）”中解包，谢谢您的帮助

您应该解包一个3元组

walk(top, topdown=True, onerror=None, followlinks=False) Directory tree generator. For each directory in the directory tree rooted at top (including top itself, but excluding '.' and '..'), yields a 3-tuple dirpath, dirnames, filenames 而且，这也行不通<代码>行是一个字符串

  for line in f:
    #reads in the second line
    if line==1:
      a_list.append(line)
      break

你可以把它改成这样

  for i, line in enumerate(f):
    #reads in the second line
    if i==1:
      a_list.append(line)
      break

但我认为这是一个更简单的方法

  import os
  a_list = []
  for dirpath, dirnames, files in os.walk(base_directory):
    for file in files:
      with open(os.path.join(dirpath, file), 'r') as f:
        next(f)                 # skip the first line
        a_list.append(next(f))  # store the second line

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谢谢你，伙计。很抱歉，如果这是一个简单的问题，但我对python还是相当陌生的。

  import os
  a_list = []
  for dirpath, dirnames, files in os.walk(base_directory):
    for file in files:
      with open(os.path.join(dirpath, file), 'r') as f:
        next(f)                 # skip the first line
        a_list.append(next(f))  # store the second line