Python 从表单将多个图像上载到Google存储

我正在尝试将多张图片（介于

1

和

40

之间的图片和

800 kb

的图片）上传到我的谷歌云存储中，存储在一个名为

shootings

的存储桶中。用户提交的表单中包含一个或多个

png

或jpeg

在此处输入代码

图像

<form action="{{url_for('picture_storage_upload')}}" method="post" enctype="multipart/form-data">
    <label class="labelOne" for="pics">Upload your pictures</label>
    <input type="file" name="uploaded_pictures" multiple="multiple" accept="image/x-png, image/jpeg"/>
    <input type="submit">
</form>

由于表单返回的是字节，因此我使用的是我的

存储类中的
push\u from\u string
方法

class Storage:
    def __init__(self, credentials, bucket_name):
        self.storage_client = storage.Client.from_service_account_json(credentials)
        self.bucket_name = bucket_name
        self.bucket = None 
        
    def push(self, local_file_name, target_file_name):
        self.bucket = self.storage_client.get_bucket(self.bucket_name)
        blob = self.bucket.blob(target_file_name)
        with open(local_file_name, 'rb') as f:
            blob.upload_from_file(f)
            
    def push_from_string(self, local_file_name, target_file_name):
        self.bucket = self.storage_client.get_bucket(self.bucket_name)
        self.bucket.blob(target_file_name).upload_from_string(local_file_name)
        return self.bucket.blob(target_file_name).public_url

我仍然收到错误“
无法转换为字节”
“
您的示例没有显示如何提取文件列表。您的错误没有显示生成它的代码行。编辑您的问题以改进。上传的文件是一个列表。使用
request.files.getlist
处理每个文件。
class Storage:
    def __init__(self, credentials, bucket_name):
        self.storage_client = storage.Client.from_service_account_json(credentials)
        self.bucket_name = bucket_name
        self.bucket = None 
        
    def push(self, local_file_name, target_file_name):
        self.bucket = self.storage_client.get_bucket(self.bucket_name)
        blob = self.bucket.blob(target_file_name)
        with open(local_file_name, 'rb') as f:
            blob.upload_from_file(f)
            
    def push_from_string(self, local_file_name, target_file_name):
        self.bucket = self.storage_client.get_bucket(self.bucket_name)
        self.bucket.blob(target_file_name).upload_from_string(local_file_name)
        return self.bucket.blob(target_file_name).public_url