Python 如何对混合类型的数据帧重新采样?
我使用以下Python代码生成数据帧df3的混合类型(浮点和字符串):Python 如何对混合类型的数据帧重新采样?,python,numpy,pandas,time-series,Python,Numpy,Pandas,Time Series,我使用以下Python代码生成数据帧df3的混合类型(浮点和字符串): df1 = pd.DataFrame(np.random.randn(dates.shape[0],2),index=dates,columns=list('AB')) df1['C'] = 'A' df1['D'] = 'Pickles' df2 = pd.DataFrame(np.random.randn(dates.shape[0], 2),index=dates,columns=list('AB')) df2['C'
df1 = pd.DataFrame(np.random.randn(dates.shape[0],2),index=dates,columns=list('AB'))
df1['C'] = 'A'
df1['D'] = 'Pickles'
df2 = pd.DataFrame(np.random.randn(dates.shape[0], 2),index=dates,columns=list('AB'))
df2['C'] = 'B'
df2['D'] = 'Ham'
df3 = pd.concat([df1, df2], axis=0)
当我将df3重采样到更高的频率时,我不会将帧重采样到更高的速率,但会忽略如何进行,我只会得到缺少的值:
df4 = df3.groupby(['C']).resample('M', how={'A': 'mean', 'B': 'mean', 'D': 'ffill'})
df4.head()
结果:
B A D
C
A 2014-03-31 -0.4640906 -0.2435414 Pickles
2014-04-30 NaN NaN NaN
2014-05-31 NaN NaN NaN
2014-06-30 -0.5626360 0.6679614 Pickles
2014-07-31 NaN NaN NaN
B A D
C
A 2014-03-31 NaN NaN Pickles
2014-06-30 NaN NaN Pickles
2014-09-30 NaN NaN Pickles
2014-12-31 -0.7429617 -0.1065645 Pickles
2015-03-31 NaN NaN Pickles
B A
C
A 2014-12-31 -0.7429617 -0.1065645
2015-12-31 -0.6245030 -0.3101057
B 2014-12-31 0.4213621 -0.0708263
2015-12-31 -0.0607028 0.0110456
当我将df3重采样到较低的频率时,我根本没有得到任何重采样:
df5 = df3.groupby(['C']).resample('A', how={'A': np.mean, 'B': np.mean, 'D': 'ffill'})
df5.head()
结果:
B A D
C
A 2014-03-31 -0.4640906 -0.2435414 Pickles
2014-04-30 NaN NaN NaN
2014-05-31 NaN NaN NaN
2014-06-30 -0.5626360 0.6679614 Pickles
2014-07-31 NaN NaN NaN
B A D
C
A 2014-03-31 NaN NaN Pickles
2014-06-30 NaN NaN Pickles
2014-09-30 NaN NaN Pickles
2014-12-31 -0.7429617 -0.1065645 Pickles
2015-03-31 NaN NaN Pickles
B A
C
A 2014-12-31 -0.7429617 -0.1065645
2015-12-31 -0.6245030 -0.3101057
B 2014-12-31 0.4213621 -0.0708263
2015-12-31 -0.0607028 0.0110456
我很确定这与混合类型有关,因为如果我用数字列重新进行年度向下采样,一切都会按预期进行:
df5b = df3[['A', 'B', 'C']].groupby(['C']).resample('A', how={'A': np.mean, 'B': np.mean})
df5b.head()
df4b = df3[['A', 'B', 'C']].groupby(['C']).resample('M', how={'A': 'mean', 'B': 'mean'})
df4b.head()
结果:
B A D
C
A 2014-03-31 -0.4640906 -0.2435414 Pickles
2014-04-30 NaN NaN NaN
2014-05-31 NaN NaN NaN
2014-06-30 -0.5626360 0.6679614 Pickles
2014-07-31 NaN NaN NaN
B A D
C
A 2014-03-31 NaN NaN Pickles
2014-06-30 NaN NaN Pickles
2014-09-30 NaN NaN Pickles
2014-12-31 -0.7429617 -0.1065645 Pickles
2015-03-31 NaN NaN Pickles
B A
C
A 2014-12-31 -0.7429617 -0.1065645
2015-12-31 -0.6245030 -0.3101057
B 2014-12-31 0.4213621 -0.0708263
2015-12-31 -0.0607028 0.0110456
但是,即使我切换到数字类型,重新采样到更高频率仍然不能像我预期的那样工作:
df5b = df3[['A', 'B', 'C']].groupby(['C']).resample('A', how={'A': np.mean, 'B': np.mean})
df5b.head()
df4b = df3[['A', 'B', 'C']].groupby(['C']).resample('M', how={'A': 'mean', 'B': 'mean'})
df4b.head()
结果:
B A
C
A 2014-03-31 -0.4640906 -0.2435414
2014-04-30 NaN NaN
2014-05-31 NaN NaN
2014-06-30 -0.5626360 0.6679614
2014-07-31 NaN NaN
这给我留下了两个问题:
即使您不能提供两部分的完整答案,也欢迎您提供部分解决方案或任何一个问题的答案 当从较低频率重新采样到较高频率时,我意识到当我想要指定填充方法时,我是在指定方式。当我这么做的时候,事情似乎起了作用
df4c = df3.groupby(['C']).resample('M', fill_method='ffill')
df4c.head()
A B D
C
A 2014-03-31 -0.2435414 -0.4640906 Pickles
2014-04-30 -0.2435414 -0.4640906 Pickles
2014-05-31 -0.2435414 -0.4640906 Pickles
2014-06-30 0.6679614 -0.5626360 Pickles
2014-07-31 0.6679614 -0.5626360 Pickles
您得到的插值选择集非常有限,但它确实可以处理混合类型
当使用nohow选项(我相信它的默认值是指)重新采样到较低的频率时,下采样确实起作用:
df5c =df3.groupby(['C']).resample('A')
df5c.head()
A B
C
A 2014-12-31 -0.1065645 -0.7429617
2015-12-31 -0.3101057 -0.6245030
B 2014-12-31 -0.0708263 0.4213621
2015-12-31 0.0110456 -0.0607028
因此,问题似乎在于如何传递选项字典或其中一个选项选项,可能是ffill,但我不确定。使用重采样和agg
自pandas-1.0.0以来。
此外,resample
方法现在就可以了
解决方案是使用与每列关联的函数或函数名定义聚合规则
df.resample(period.agg)(聚合规则)
更多关于聚合规则的示例
工作示例
准备测试数据:
将numpy导入为np
作为pd进口熊猫
日期=pd.日期范围(“2021-02-09”,“2021-04-09”,freq=“1D”)
df1=pd.DataFrame(np.random.randn(dates.shape[0],2),index=dates,columns=list('AB'))
df1['C']='A'
df1['D']='Pickles'
df2=pd.DataFrame(np.random.randn(dates.shape[0],2),index=dates,columns=list('AB'))
df2['C']='B'
df2['D']='Ham'
df3=pd.concat([df1,df2],轴=0)
打印(df3)
输出:
A B C D
2021-02-09 2.591285 2.455686 A Pickles
2021-02-10 0.753461 -0.072643 A Pickles
2021-02-11 -0.351667 -0.025511 A Pickles
2021-02-12 -0.896730 0.004512 A Pickles
2021-02-13 -0.493139 -0.770514 A Pickles
... ... ... .. ...
2021-04-05 1.615935 1.152517 B Ham
2021-04-06 -0.067654 -0.858186 B Ham
2021-04-07 0.085587 -0.848542 B Ham
2021-04-08 -0.371983 0.088441 B Ham
2021-04-09 0.681501 0.235328 B Ham
[120 rows x 4 columns]
A B C D
2021-02-28 0.025987 3.886781 A Ham
2021-03-31 0.081423 -5.492928 A Ham
2021-04-30 0.239309 -3.344334 A Ham
每月重新取样:
agg_规则={“A”:“平均”、“B”:“总和”、“C”:“第一”、“D”:“最后一个”,}
df4=df3.重采样(“M”).agg(agg_规则)
打印(df4)
输出:
A B C D
2021-02-09 2.591285 2.455686 A Pickles
2021-02-10 0.753461 -0.072643 A Pickles
2021-02-11 -0.351667 -0.025511 A Pickles
2021-02-12 -0.896730 0.004512 A Pickles
2021-02-13 -0.493139 -0.770514 A Pickles
... ... ... .. ...
2021-04-05 1.615935 1.152517 B Ham
2021-04-06 -0.067654 -0.858186 B Ham
2021-04-07 0.085587 -0.848542 B Ham
2021-04-08 -0.371983 0.088441 B Ham
2021-04-09 0.681501 0.235328 B Ham
[120 rows x 4 columns]
A B C D
2021-02-28 0.025987 3.886781 A Ham
2021-03-31 0.081423 -5.492928 A Ham
2021-04-30 0.239309 -3.344334 A Ham