围绕椭圆形状的质心旋转四个对象,Python
好的。。。我的数学不是很好(甚至没有完成我们的高中版本),现在真的很累,但我需要围绕着质心椭圆环绕四个物体,并且已经被卡住了一段时间,但这并不是说我没有尝试过或者没有独自去任何地方。这就是我到目前为止的想法:围绕椭圆形状的质心旋转四个对象,Python,python,center,points,centroid,orbit,Python,Center,Points,Centroid,Orbit,好的。。。我的数学不是很好(甚至没有完成我们的高中版本),现在真的很累,但我需要围绕着质心椭圆环绕四个物体,并且已经被卡住了一段时间,但这并不是说我没有尝试过或者没有独自去任何地方。这就是我到目前为止的想法: from math import cos,sin,pi,sqrt,atan2 def orbit(p, deg, pivot=(0.32563325, 0.123498),ellipse=(0.5, 0.743992)): # p = current (x,y)-position
from math import cos,sin,pi,sqrt,atan2
def orbit(p, deg, pivot=(0.32563325, 0.123498),ellipse=(0.5, 0.743992)):
# p = current (x,y)-position of current object,
# Pivot = (x,y)-position of point to orbit around,
# retrieved by centroid((x1,y1),(x2,y2),(x3,y3),(x4,y4))
# Ellipse = (width,height) of ellipse to rotate around
# retrieved by ellipse((x1,y1),(x2,y2),(x3,y3),(x4,y4))
px,py = pivot
if ellipse == (0.0,0.0):
o = polar(p[0]-px,p[1]-py)[0]
xr,yr = 1.0,1.0
else:
ew,eh = ellipse
if ew < eh:
o = eh/2 # Distance to the point most far away from the middle of the ellipse (Outer radius)
xr = ew/eh # Horizontal ratio of ellipse so we can move it back properly into ellipse after performing circular orbit
yr = 1.0 # Verical movement will not be affected because it's on the large axis
else:
o = ew/2
xr = 1.0
yr = eh/ew
x,y = p[0]-px,p[1]-py # Subtract pivot's position (that's the the point I want to orbit around)
d,a = polar(x,y) # Get angle
x,y = rect(o,a+deg) # Move point as far away from middle as it will be as most and make circular orbit around pivot by deg degrees
x,y = x*xr,y*yr # Move points back to elliptic shape by multiplying positions with according ratio <--- I guess it's here something goes wrong
x,y = x+px,y+py # Move point back to original position by adding pivot's positions
return x,y
# Other functions
def centroid(*points):
x,y = izip(*points)
return (sum(x) / len(points), sum(y) / len(points))
def ellipse(*points):
x,y = izip(*points)
xd,yd = max(x)-min(x),max(y)-min(y)
return (xd,yd)
def polar(x,y):
d = sqrt(x**2 + y**2)
a = atan2(y,x) * (180.0/pi)
return d, a
def rect(d,a):
x = d * cos(a*pi/180.0)
y = d * sin(a*pi/180.0)
return x, y
从数学导入cos、sin、pi、sqrt、atan2
def轨道(p,度,枢轴=(0.32563325,0.123498),椭圆=(0.5,0.743992)):
#p=当前(x,y)-当前对象的位置,
#枢轴=(x,y)-要环绕的点的位置,
#通过质心((x1,y1)、(x2,y2)、(x3,y3)、(x4,y4))检索
#椭圆=(宽度、高度)要旋转的椭圆
#通过椭圆((x1,y1)、(x2,y2)、(x3,y3)、(x4,y4))检索
px,py=枢轴
如果椭圆==(0.0,0.0):
o=极性(p[0]-px,p[1]-py)[0]
xr,yr=1.0,1.0
其他:
ew,eh=椭圆
如果ew x、 y=x*xr,y*yr#通过将位置乘以相应的比率将点移回椭圆形状这封装了每个椭圆的数学,并显示了示例用法;您必须为您想要的任何输出添加代码
from math import sin, cos, pi
class Ellipse(object):
@classmethod
def fromBox(cls, p1=(-1.,-1.), p2=(1.,1.), period=1., offs=0., clockwise=False):
"""
Construct an Ellipse from an axis-aligned bounding box
p1, p2 diagonally-opposed corners of the bounding box
period time for a complete orbit
offs offset into initial rotation
clockwise direction of rotation
"""
x1,y1 = p1
x2,y2 = p2
# find center point
cx, cy = (x1 + x2)*0.5, (y1 + y2)*0.5
# find major and minor semi-axes and corresponding theta
a,b = abs(x2 - x1)*0.5, abs(y2 - y1)*0.5
if a >= b:
theta = 0.0
else:
a,b = b,a
theta = pi/2
# return an Ellipse object
return cls(cx, cy, a, b, theta, period, offs, clockwise)
def __init__(self, x=0., y=0., a=1., b=1., theta=0., period=1., offs=0., clockwise=False):
"""
Create an ellipse
x,y center point
a semi-major axis
b semi-minor axis
theta major axis inclination (in radians)
period time for a complete orbit
offs offset into initial rotation
clockwise direction of rotation
"""
self.x = x
self.y = y
self.period = -period if clockwise else period
self._freq = self.period / (2. * pi)
self.offs = offs
s_th = sin(theta)
c_th = cos(theta)
self._ast = a * s_th
self._act = a * c_th
self._bst = b * s_th
self._bct = b * c_th
def at(self, t):
"""
Evaluate the ellipse at time t
"""
_t = (t - self.offs) * self._freq
st = sin(_t)
ct = cos(_t)
return self.x + self._act*ct - self._bst*st, self.y + self._act*st + self._bst*ct
def main():
a = Ellipse.fromBox((-0.67436675, -0.376502), (1.32563325, 0.623498))
b = Ellipse(0.32563325, 0.123498, 0.9, 0.6, pi/6)
c = Ellipse(0.32563325, 0.123498, 1.1, 0.5, pi/4)
d = Ellipse(0.32563325, 0.123498, 1.0, 0.5, pi/2)
t_step = 0.03
for t in xrange(200):
drawCircle(a.at(t*t_step), "red")
drawCircle(b.at(t*t_step), "blue")
drawCircle(c.at(t*t_step), "green")
drawCircle(d.at(t*t_step), "yellow")
if __name__=="__main__":
main()
当您尝试代码时会发生什么?您希望发生什么?椭圆的x和y坐标可以描述为参数的函数(通常称为t
)。可以通过增加参数来“旋转”对象。我想查看维基百科和math.stackexchange.com,了解有关椭圆参数函数的更多信息。@Trasp:你不能使用简单的双圆技术吗?