Python 获取简单Tkinter程序的错误

我一直在尝试使用Tkinter和Python编写一个简单的程序。您只需单击按钮，它会根据您单击的按钮更新某些标签。这是我的代码：

from tkinter import *

apples = 0
gold = 0

def pick():
    global apples
    apples = apples + 1


def sell():
    global apples
    global gold
    gold = gold + (apples * 10)
    apples = 0

app = Tk()

app.title("Apple Picking Simulator 2014")
app.geometry("400x300+100+60")

label1 = Label(text = "Welcome to Apple Picking Simulator 2014!").pack()
Label().pack()
label2 = Label(text = "Apples: " + apples).pack()
label3 = Label(text = "Gold: " + gold).pack()
button1 = Button(text = "Pick Apple", command = pick).pack()
button2 = Button(text = "Sell Apples", command = sell).pack()

app.mainloop()

现在，每当我尝试运行程序时，我都会得到错误：

TypeError: Can't convert 'int' object to str implicitly

---

我知道它不能将整数转换成字符串，但我已经尝试了所有的方法，但我似乎无法让它工作。有没有一种简单的方法可以在窗口上显示苹果和黄金的数字，并让它们在我每次单击“选择或出售”按钮时更新？谢谢。

尝试将整数连接到字符串是导致错误的原因。您需要使用

替换：

label2 = Label(text = "Apples: " + apples).pack()
label3 = Label(text = "Gold: " + gold).pack()

与：

固定源代码：

from tkinter import *

apples = 0
gold = 0

def pick():
    global apples
    apples = apples + 1


def sell():
    global apples
    global gold
    gold = gold + (apples * 10)
    apples = 0

app = Tk()

app.title("Apple Picking Simulator 2014")
app.geometry("400x300+100+60")

label1 = Label(text = "Welcome to Apple Picking Simulator 2014!").pack()
Label().pack()
label2 = Label(text = "Apples: " + str(apples)).pack()
label3 = Label(text = "Gold: " + str(gold)).pack()
button1 = Button(text = "Pick Apple", command = pick).pack()
button2 = Button(text = "Sell Apples", command = sell).pack()

app.mainloop()

---

您的问题是，您正在尝试连接字符串和整数：

label2 = Label(text = "Apples: " + apples).pack()
label3 = Label(text = "Gold: " + gold).pack()

这会产生一个错误：

>>> apples = 0
>>> "Apples: ", apples
('Apples: ', 0)
>>> "Apples: " + apples
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: cannot concatenate 'str' and 'int' objects
>>> 

---

谢谢大家的回答。这确实消除了错误。我以为我以前做过。但是，仍然存在一个问题。每次我点击一个按钮，它不会用新数量的苹果或黄金更新标签。有什么办法可以做到这一点吗？或者这不起作用吗？@Hero2016我不知道如何帮助您，但您可能需要添加一些代码来更改“选择和销售”回调中的标签。你可以发布一个关于这个的新问题。

>>> apples = 0
>>> "Apples: ", apples
('Apples: ', 0)
>>> "Apples: " + apples
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: cannot concatenate 'str' and 'int' objects
>>> 

from tkinter import *

apples = 0
gold = 0

def pick():
    global apples
    apples = apples + 1


def sell():
    global apples
    global gold
    gold = gold + (apples * 10)
    apples = 0

app = Tk()

app.title("Apple Picking Simulator 2014")
app.geometry("400x300+100+60")

label1 = Label(text = "Welcome to Apple Picking Simulator 2014!").pack()
Label().pack()
label2 = Label(text = "Apples: " + str(apples)).pack()
label3 = Label(text = "Gold: " + str(gold)).pack()
button1 = Button(text = "Pick Apple", command = pick).pack()
button2 = Button(text = "Sell Apples", command = sell).pack()

app.mainloop()