Python 如何从datetime对象中删除pytz时区?
有没有一种简单的方法可以从pytz datetime对象中删除时区?Python 如何从datetime对象中删除pytz时区?,python,timezone,pytz,Python,Timezone,Pytz,有没有一种简单的方法可以从pytz datetime对象中删除时区? e、 g.在本例中,从dt_tz重建dt: >>> import datetime >>> import pytz >>> dt = datetime.datetime.now() >>> dt datetime.datetime(2012, 6, 8, 9, 27, 32, 601000) >>> dt_tz = pytz.utc.lo
e、 g.在本例中,从
dt_tz
重建dt
:
>>> import datetime
>>> import pytz
>>> dt = datetime.datetime.now()
>>> dt
datetime.datetime(2012, 6, 8, 9, 27, 32, 601000)
>>> dt_tz = pytz.utc.localize(dt)
>>> dt_tz
datetime.datetime(2012, 6, 8, 9, 27, 32, 601000, tzinfo=<UTC>)
导入日期时间
>>>进口皮茨
>>>dt=datetime.datetime.now()
>>>dt
datetime.datetime(2012,6,8,9,27,32,601000)
>>>dt_tz=pytz.utc.localize(dt)
>>>德图茨
datetime.datetime(2012,6,8,9,27,32,601000,tzinfo=)
要从datetime对象中删除时区(tzinfo),请执行以下操作:
# dt_tz is a datetime.datetime object
dt = dt_tz.replace(tzinfo=None)
如果您正在使用类似的库,那么您可以通过简单地将arrow对象转换为datetime对象来删除时区,然后执行与上面示例相同的操作
# <Arrow [2014-10-09T10:56:09.347444-07:00]>
arrowObj = arrow.get('2014-10-09T10:56:09.347444-07:00')
# datetime.datetime(2014, 10, 9, 10, 56, 9, 347444, tzinfo=tzoffset(None, -25200))
tmpDatetime = arrowObj.datetime
# datetime.datetime(2014, 10, 9, 10, 56, 9, 347444)
tmpDatetime = tmpDatetime.replace(tzinfo=None)
##############################################################################
# MySQL example! where MySQL doesn't support timezones with its DATETIME type!
##############################################################################
arrowObj = arrow.get('2014-10-09T10:56:09.347444-07:00')
arrowDt = arrowObj.to("utc").datetime
# inserts datetime.datetime(2014, 10, 9, 17, 56, 9, 347444, tzinfo=tzutc())
insertIntoMysqlDatabase(arrowDt)
# returns datetime.datetime(2014, 10, 9, 17, 56, 9, 347444)
dbDatetimeNoTz = getFromMysqlDatabase()
# cannot compare timzeone aware and timezone naive
dbDatetimeNoTz == arrowDt # False, or TypeError on python versions before 3.3
# compare datetimes that are both aware or both naive work however
dbDatetimeNoTz == arrowDt.replace(tzinfo=None) # True