Python-addfind和Replace语句

非常感谢您将我的代码恢复到当前状态，但我一直在碰壁

代码将excel文件读入列表，然后在文件夹中循环并重命名文件，但它会按照列表的顺序执行此操作，然后从第一个文件开始，一直到最后一个文件，因此如果我手动对excel列表和文件本身进行排序，我可以准确地重命名它们，但我希望添加一个find（）这样我可以使这个程序更灵活

目标-添加find（），这样它将循环浏览当前文件名列表（在excel中），然后在所选文件夹中找到正确的文件，然后将其重命名为正确的新名称

当前工作代码（不带Find（））：

我试图在代码中添加if（），但它只是说：“找不到文件”

将此添加到循环原始文件名列并添加到列表中：

def originalFilenameRange(startCol, startRow, endCol, endRow, sheet):
    originalFilenameRange = []
    # Loops through selected Rows
    for i in range(startRow, endRow + 1, 1):
        # Appends the row to a RowSelected list
        rowSelected = []
        for j in range(startCol, endCol + 1, 1):
            rowSelected.append(sheet.cell(row=i, column=j).value)
        # Adds the RowSelected List and nests inside the rangeSelected
        originalFilenameRange.append(rowSelected)

    return originalFilenameRange

# Takes: start cell, end cell, and sheet you want to copy from.
def copyRange(startCol, startRow, endCol, endRow, sheet):
    rangeSelected = []
    # Loops through selected Rows
    for i in range(startRow, endRow + 1, 1):
        # Appends the row to a RowSelected list
        rowSelected = []
        for j in range(startCol, endCol + 1, 1):
            rowSelected.append(sheet.cell(row=i, column=j).value)
        # Adds the RowSelected List and nests inside the rangeSelected
        rangeSelected.append(rowSelected)

    return rangeSelected


def renameFiles():
    print('Processing...')

    # Make a folder for the files
    current_directory = os.getcwd()
    folder_n_path = os.path.join(current_directory, folderDestination)
    print("Files saved to: " + folder_n_path)
    try:
        newFolder = os.makedirs(folder_n_path)

    except:
        print("Folder already exists")
        return

    # Get the Data to make the file names
    selectedRange = copyRange(1, 1, 2, 2, file_names_sheet)
    filesToFind = originalFilenameRange(3,1,3,2094,file_names_sheet)
    print(selectedRange)
    print(filesToFind)
    print (folderSource)

    for filename in os.listdir(folderSource):
        for i, filename in zip(selectedRange, os.listdir(folderSource)):
            filename = os.path.join(folderSource, filename)
            print (filename)
            if filename in filesToFind:
                file_name = i[0] + " " + i[1] + ".jpg"
                filename = os.path.join(folderSource, filename)
                file_name = os.path.join(folderDestination, file_name)
                shutil.copy(filename, file_name)
                print("Done")
            else:
                print ("File does not exist: " + filename)

go = renameFiles()

所有内容都正确打印到此点，然后通过此循环跳转到“未找到文件”：

def originalFilenameRange(startCol, startRow, endCol, endRow, sheet):
    originalFilenameRange = []
    # Loops through selected Rows
    for i in range(startRow, endRow + 1, 1):
        # Appends the row to a RowSelected list
        rowSelected = []
        for j in range(startCol, endCol + 1, 1):
            rowSelected.append(sheet.cell(row=i, column=j).value)
        # Adds the RowSelected List and nests inside the rangeSelected
        originalFilenameRange.append(rowSelected)

    return originalFilenameRange

# Takes: start cell, end cell, and sheet you want to copy from.
def copyRange(startCol, startRow, endCol, endRow, sheet):
    rangeSelected = []
    # Loops through selected Rows
    for i in range(startRow, endRow + 1, 1):
        # Appends the row to a RowSelected list
        rowSelected = []
        for j in range(startCol, endCol + 1, 1):
            rowSelected.append(sheet.cell(row=i, column=j).value)
        # Adds the RowSelected List and nests inside the rangeSelected
        rangeSelected.append(rowSelected)

    return rangeSelected


def renameFiles():
    print('Processing...')

    # Make a folder for the files
    current_directory = os.getcwd()
    folder_n_path = os.path.join(current_directory, folderDestination)
    print("Files saved to: " + folder_n_path)
    try:
        newFolder = os.makedirs(folder_n_path)

    except:
        print("Folder already exists")
        return

    # Get the Data to make the file names
    selectedRange = copyRange(1, 1, 2, 2, file_names_sheet)
    filesToFind = originalFilenameRange(3,1,3,2094,file_names_sheet)
    print(selectedRange)
    print(filesToFind)
    print (folderSource)

    for filename in os.listdir(folderSource):
        for i, filename in zip(selectedRange, os.listdir(folderSource)):
            filename = os.path.join(folderSource, filename)
            print (filename)
            if filename in filesToFind:
                file_name = i[0] + " " + i[1] + ".jpg"
                filename = os.path.join(folderSource, filename)
                file_name = os.path.join(folderDestination, file_name)
                shutil.copy(filename, file_name)
                print("Done")
            else:
                print ("File does not exist: " + filename)

go = renameFiles()

---

看起来

filesToFind

是一个基于

print（filesToFind）

结果的嵌套列表。在您的比较行中：

if filename in filesToFind:

您正在将字符串与列表中的列表进行比较，该列表总是失败

您需要将

文件名

字符串与字符串列表进行比较

['filename'，'filename2'，…]

。注意到细微的差别了吗

查看您的代码，您正在将

filesToFind

设置为：

filesToFind = originalFilenameRange(3,1,3,2094,file_names_sheet)

因此，您需要更改

originalFilenameRange

方法以返回字符串列表，而不是列表列表

一个简单的单行代码更改可以使您的代码正常工作，它位于

originalFilenameRange

方法的这一行：

originalFilenameRange.append(rowSelected)

为此：

originalFilenameRange.append(rowSelected[0])

---

如果你打印

filesToFind

你得到了预期的结果吗？是的，这增加了我的困惑：

print（selectedRange）给出：[000197'，Marie Corrales']，[000232'，Richard Methvin']

打印（filesToFind）给出：[000197.jpg']，['000232.jpg']打印（文件名）给出：C:/Users/jx0062/Documents/PythonTest/Photos-Copy\000197.jpg文件不存在：filename C:/Users/jx0062/Documents/PythonTest/Photos-Copy\000232.jpg文件不存在：filename因此它似乎正确地加入了文件路径，因为当我右键单击并复制到路径时，我得到以下结果：“C:\Users\jx0062\Documents\PythonTest\Photos-Copy\000197.jpg”是否与绝对路径和相对路径有关？将它们添加到一个列表中，这样很好，现在

打印（fiilesToFind）

给出：

['000197.jpg'，'000232.jpg']

打印（文件名）

给出：

C:/Users/jx0062/Documents/PythonTest/Photos-Copy\000197.jpg

，与以前一样，但我仍然得到“文件不存在：文件名”，并且不会因此移动或重命名任何内容。如果语句在哪里，我是否需要移动到

语句所在的位置？它是否应该在
for
循环之外？我将试一试（添加常量）。感谢您的帮助！