在python中导入函数

我正在尝试创建一个菜单，用户可以在其中选择他/她想要运行的程序的哪一部分。当我导入函数时，计算机会自动运行它，而不是等待用户输入。我应该怎么做才能只在调用时运行函数？我的代码：

    import hangman

    menu = raw_input("""Welcome to Menu, please choose from the following options: 
    1. Hangman game
    2.
    3. 
    4. Exit
    """)

    if menu == 1: 
        hangman()
    elif menu == 2:
        "Something"
    elif menu == 3:
        "Something"
    elif menu == 4:
        print "Goodbye"
    else:
        print "Sorry, invalid input" 

hangman.py的代码如下所示：

import random

words = ["monitor", "mouse", "cpu", "keyboard", "printer",]  

attempts = [] # Stores user input

randomWord = random.choice(words) # Computer randomly chooses the word

noChar = len(randomWord) # Reads number of characters in the word

print randomWord , noChar
print "Hello, Welcome to the game of Hangman. You have to guess the given word. The first word has", noChar, " letters."

def game():    
    guess = raw_input ("Please choose letter")
    attempts.append(guess) # Adds user input to the list
    print (attempts)

    if guess in randomWord: 
        print "You have guessed the letter" 
    else: 
        print "Please try again"


while True:
    game()
    chance = raw_input ("Have a guess")
    if chance == randomWord:
        print "Congratulations, you have won!"
        break

---

如果没有看到

hangman.py

，我会假设它直接包含运行hangman游戏的代码，而不是封装在函数中。如果是这样的话，您创建了一个模块，没有函数（还没有）

把代码包起来

def run_hangman():
    # Your existing code, indented by 4 spaces
    # ...

按如下方式导入：

from hangman import run_hangman

run_hangman()

def main():
    stuff = raw_input('Starting new game. Please enter stuff to do things')
    run_hangman(stuff)


def run_hangman(options):
    if options == 'SKIP':
        important_values = 5
        vales_set_by_user = 'Player 1'
    else:
        values_set_by_user = options

    rest_of_code()

最后调用如下函数：

from hangman import run_hangman

run_hangman()

def main():
    stuff = raw_input('Starting new game. Please enter stuff to do things')
    run_hangman(stuff)


def run_hangman(options):
    if options == 'SKIP':
        important_values = 5
        vales_set_by_user = 'Player 1'
    else:
        values_set_by_user = options

    rest_of_code()

---

这是开始菜单：

import hangman
option = raw_input('1) Start Normal\n2) Quick Start\n3) Default') # '\n' is a new line
if option == '1':
    hangman.main()
elif option == '2':
    hangman.run_hangman('SKIP')
elif option == '3':
    handman.run_hangman('Default User')

在你的刽子手代码里，你想对它进行调制。你应该有这样的东西：

from hangman import run_hangman

run_hangman()

def main():
    stuff = raw_input('Starting new game. Please enter stuff to do things')
    run_hangman(stuff)


def run_hangman(options):
    if options == 'SKIP':
        important_values = 5
        vales_set_by_user = 'Player 1'
    else:
        values_set_by_user = options

    rest_of_code()

---

相关：。并使用

hangman.hangman（）

而不仅仅是

hangman（）

。。。Python的

import

与C的

include

不同。它创建一个模块对象，该对象将您在该模块中定义的内容作为属性。如果您在

hangman.py

文件中有一个名为

hangman

的函数，您还可以使用

from hangman import hangman

将菜单转换为int（或将菜单与字符串进行比较），因为原始输入返回字符串。try:menu=int（menu）除了value错误：打印“这不是一个有效的选项！！”我添加了刽子手代码。问题可能是我已经在itNo中创建了一个函数，问题是您的

while True:

块不在函数中-这意味着在导入模块时它将立即执行。将其包装在一个函数

def run_hangman（）：

中，然后像我描述的那样导入该函数，您应该会很好。