使用python basemap绘制多个greatcircle图

解决此问题时遇到困难：

从阵列绘制多条大圆路径

错误消息：

回溯（最近一次调用last）：文件“example.py”，第41行，在 eq_map.drawgreatcircle（y，x，y2，x2，线宽=6，color='b'）文件“/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/site packages/mpl_工具包/basemap/init.py”， 第2893行，在drawgreatcircle中 npoints=int（（dist+0.5*1000.*del_s）/（1000.*del_s））类型错误：只能将列表（而不是“float”）连接到列表

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Python代码：

import csv

# Open the data file.
filename = 'sample.csv'

# Create empty lists for the latitudes and longitudes.
lats, lons = [], []
lats2, lons2 = [], []

# Read through the entire file, skip the first line,
#  and pull out just the lats and lons.
with open(filename) as f:
    # Create a csv reader object.
    reader = csv.reader(f)

    # Ignore the header row.
    next(reader)

    # Store the latitudes and longitudes in the appropriate lists.
    for row in reader:
        lats.append(float(row[1]))
        lons.append(float(row[2]))
        lats2.append(float(row[4]))
        lons2.append(float(row[5]))        

from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
import numpy as np

eq_map = Basemap(projection='merc',llcrnrlat=-80,urcrnrlat=80,llcrnrlon=-180,urcrnrlon=180,lat_ts=20,resolution='c')

eq_map.drawcoastlines()
eq_map.drawcountries()
eq_map.fillcontinents(color = 'gray')
eq_map.drawmapboundary()
eq_map.drawmeridians(np.arange(0, 360, 30))
eq_map.drawparallels(np.arange(-90, 90, 30))

x,y = eq_map(lons, lats)
x2,y2 = eq_map(lons2,lats2)
eq_map.drawgreatcircle(y,x,y2,x2,linewidth=6,color='b')

plt.show()

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Sample.csv

Origin,origLat,origLon,Dest,destLat,destLon
"jfk",40.641311,-73.778139,"lax",33.941589,-118.40853
"teb",40.849023,-74.062953,"mia",34.730283,136.508588

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您的LON和LAT当前在列表中。您需要遍历以获得坐标

print(type(lons))

以下是我的想法：

for x, y, x2, y2 in zip(lats[0::1], lons[0::1], lats2[0::1], lons2[0::1]):
    eq_map.drawgreatcircle(x, y, x2, y2, linewidth=2, color='b')

除非你也想要创建绘图，否则你不需要

x,y = eq_map(lons, lats)
x2,y2 = eq_map(lons2,lats2)

有情节

for lats, lons, lats2, lons2 in zip(lats[0::1], lons[0::1], lats2[0::1], lons2[0::1]):
    x,y = eq_map(lons, lats)
    x2,y2 = eq_map(lons2,lats2)
    eq_map.plot(x, y, marker='.', color='r', markersize=10)
    eq_map.plot(x2, y2, marker='.', color='r', markersize=10)
    eq_map.drawgreatcircle(lons, lats, lons2, lats2, linewidth=2, color='b')

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您的LON和LAT当前在列表中。您需要遍历以获得坐标

print(type(lons))

以下是我的想法：

for x, y, x2, y2 in zip(lats[0::1], lons[0::1], lats2[0::1], lons2[0::1]):
    eq_map.drawgreatcircle(x, y, x2, y2, linewidth=2, color='b')

除非你也想要创建绘图，否则你不需要

x,y = eq_map(lons, lats)
x2,y2 = eq_map(lons2,lats2)

有情节

for lats, lons, lats2, lons2 in zip(lats[0::1], lons[0::1], lats2[0::1], lons2[0::1]):
    x,y = eq_map(lons, lats)
    x2,y2 = eq_map(lons2,lats2)
    eq_map.plot(x, y, marker='.', color='r', markersize=10)
    eq_map.plot(x2, y2, marker='.', color='r', markersize=10)
    eq_map.drawgreatcircle(lons, lats, lons2, lats2, linewidth=2, color='b')