如何在python中将unicode列表转换为utf8格式？

我正试图找到一种有效的方法，将列表转换为utf8格式，同时又不会弄乱我的writer.writerowrowToken-基本上就是我用来为列表创建单独的列的方法。

@DimitrisJim现在删除的答案是正确的。您是否不小心使用了writerow而不是writerow

以UTF-8编码的输出文件内容：

#!python2
#coding:utf8

import csv

firstName = u'John Joe 马克'.split()
lastName = u'Doe Blow 多路能'.split()
phdName = u'a b c'.split()
universityName = u'd e f'.split()
departmentName = u'g h i'.split()

with open('assignmentTest.csv', 'wb') as finale:
    writer = csv.writer(finale) #creates csv file to write final lists into
    finalRows = zip(firstName, lastName, phdName, universityName, departmentName) #put all of the lists into another lists so that the outputs are in 'column form' as opposed to rows
    for rowToken in finalRows: #puts each element of each list together in the same order
        writer.writerow([col.encode('utf8') for col in rowToken])

---

您是否考虑过只转换每个元素？另外，如果你有一个输入文件，你应该考虑使用那个文件对象作为生成器，而不是把它的内容读入一个列表中，然后它被顺序地处理和写入。为什么你要通过“B”模式来打开？我试着转换每个元素，但是只是相同的错误。在对Windows产生影响的平台上，csv.reader或csv.writer需要b。看。

#!python2
#coding:utf8

import csv

firstName = u'John Joe 马克'.split()
lastName = u'Doe Blow 多路能'.split()
phdName = u'a b c'.split()
universityName = u'd e f'.split()
departmentName = u'g h i'.split()

with open('assignmentTest.csv', 'wb') as finale:
    writer = csv.writer(finale) #creates csv file to write final lists into
    finalRows = zip(firstName, lastName, phdName, universityName, departmentName) #put all of the lists into another lists so that the outputs are in 'column form' as opposed to rows
    for rowToken in finalRows: #puts each element of each list together in the same order
        writer.writerow([col.encode('utf8') for col in rowToken])

John,Doe,a,d,g
Joe,Blow,b,e,h
马克,多路能,c,f,i