python中的If条件在循环中

我在if条件的正确语法方面面临困难。我想应用这个条件来检查字符串的相等性。但我尝试这样做的方式给了我一个错误：

AttributeError: 'str' object has no attribute 'any'
for :
for a in prod_comm:
    if prod_comm['label']==('label":"neg"}').any():
        prod_pos.append(a)

或：

我想做的是： 有一个包含两列的数据框-c和label。我想根据标签类型将此数据帧划分为不同的文件，即：

label":"neg"}    or     label":"pos"}

我如何进行分类？我猜我使用的语法有问题，但是在网上找不到正确的语法

Example dataset:
        comment                                  label
    0   need 3 bhk house                         "label": "neg"}
    2   tried to list my property                "label": "neg"}
    22  i have issue with the map                "label": "neg"}
    24  also help with the rental agreements     "label": "pos"}
    37  sort option should be available.         "label": "pos"}

expected output:
two datasets:
prod_pos - with the comments corresponding to label: "label": "pos"}
prod_neg - with the comments corresponding to label: "label": "neg"}
i.e. 

prod_pos:
    comment                                  label
24  also help with the rental agreements     "label": "pos"}
37  sort option should be available.         "label": "pos"}

prod_neg:
        comment                                  label
    0   need 3 bhk house                         "label": "neg"}
    2   tried to list my property                "label": "neg"}
    22  i have issue with the map                "label": "neg"}

---

谢谢你的帮助

您似乎有一个熊猫数据帧，所以可以这样做：

给定您的数据帧：

df
                                comment          label
0                      need 3 bhk house  label: "neg"}
1             tried to list my property  label: "neg"}
2             i have issue with the map  label: "neg"}
3  also help with the rental agreements  label: "pos"}
4      sort option should be available.  label: "pos"}

只要做：

df_neg = df[df.label=='label: "neg"}']
df_pos = df[df.label=='label: "pos"}']

其中：

df_neg
                     comment          label
0           need 3 bhk house  label: "neg"}
1  tried to list my property  label: "neg"}
2  i have issue with the map  label: "neg"}

df_pos
                                comment          label
3  also help with the rental agreements  label: "pos"}
4      sort option should be available.  label: "pos"}

---

HTH

谢谢

（'label:“neg”}'），您能发布代表性的数据、代码、错误和其他人可以运行的所需输出吗？any（）

-您明确指出

。any（）

应该在

'label:“neg”}'

上调用。请重新考虑一下括号的用法。我试过在没有括号的情况下使用它。它仍然给出了相同的错误注释。

df_neg
                     comment          label
0           need 3 bhk house  label: "neg"}
1  tried to list my property  label: "neg"}
2  i have issue with the map  label: "neg"}

df_pos
                                comment          label
3  also help with the rental agreements  label: "pos"}
4      sort option should be available.  label: "pos"}