Python集().IsubSet()未按预期工作
我试图使用Python集().IsubSet()未按预期工作,python,python-2.7,set,Python,Python 2.7,Set,我试图使用set().issubset()来比较序列。正如你所能想象的,它没有按预期工作;)预告:抱歉,代码太长了 class T(object): def __init__(self, value, attributes = None): self.value = value self.attributes = Attributes(attributes) def __eq__(self, other): if not isinstance(other, T)
set().issubset()
来比较序列。正如你所能想象的,它没有按预期工作;)预告:抱歉,代码太长了
class T(object):
def __init__(self, value, attributes = None):
self.value = value
self.attributes = Attributes(attributes)
def __eq__(self, other):
if not isinstance(other, T):
return False
if self.value == other.value and self.attributes == other.attributes:
return True
else:
return False
def __ne__(self, other):
if not isinstance(other, T):
return True
if self.value != other.value or self.attributes != other.attributes:
return True
else:
return False
class Attributes(dict):
def __init__(self, attributes):
super(dict, self)
self.update(attributes or dict())
def __eq__(self, other):
if self.items() == other.items():
return True
else:
return False
def __ne__(self, other):
if not self.items() == other.items():
return True
else:
return False
def __cmp__(self, other):
return self.items().__cmp__(other.items())
x = [T("I", {'pos': 0}), T("am", {'pos': 1}), T("a", {'pos': 2}), T("test", {'pos': 3})]
y = [T("a", {'pos': 2}), T("test", {'pos': 3})]
xx = set(x)
yy = set(y)
assert y[0] == x[2], "__eq__ did fail, really?" #works
assert y[1] == x[3], "__eq__ did fail, really?" #works
assert xx-(yy-xx) == xx, "set subtract not working" #works, but is nonsense. see accepted answer
assert not xx.issubset(yy), "i am doing it wrong..." #works
assert yy.issubset(xx), "issubset not working :(" #FAILS!
运行上述代码会导致最后一次断言失败:
$ python
Python 2.7.2 (v2.7.2:8527427914a2, Jun 11 2011, 15:22:34)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import issubsettest
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "issubsettest.py", line 52, in <module>
assert yy.issubset(xx), "issubset not working :("
AssertionError: issubset not working :(
>>>
$python
Python 2.7.2(v2.7.2:8527414a2,2011年6月11日,15:22:34)
[GCC 4.2.1(苹果公司建造5666)(dot 3)]关于达尔文
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回溯(最近一次呼叫最后一次):
文件“”,第1行,在
文件“issubsettest.py”,第52行,在
断言yy.issubset(xx),“issubset不工作:(”
AssertionError:issubset不工作:(
>>>
我在这里遗漏了什么?您的对象正在被其
id
散列(您没有覆盖\uuuuuuhash\uuuuuu
)。当然,它们不是子集,因为xx
和yy
包含唯一的对象
为了做到这一点,您需要使用某种\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
函数
class T(object):
#<snip> ...
def __hash__(self):
return hash(self.value)
#... </snip>
这应该很明显为什么这是
真的
我认为这是因为用户我认为问题在于你的类T
没有覆盖方法\uuuuuuuhash\uuuuuu
,其实例在散列集合中不可用。我刚刚用Python 3.3测试了您的代码,它给出了错误:TypeError:unhabable type:'T'
在xx=set(x)行上
所以肯定是缺少\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
。然后解释他应该如何修复它。@JBernardo——修复它完全是另一回事。OP需要以某种方式覆盖\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu…这有帮助吗?好的,我明白了,谢谢!让我困惑的是,xx-(yy-xx)
似乎起到了一些作用。但我认为它所做的仅仅是yy-set()
括号内和xx-set()
之后。事后看来,这个断言甚至是完全错误的。我认为我无法通过减法证明任何东西。@mgilson是的!谢谢你的解释!
xx - set([]) == xx