Python:1个函数可以接受来自2个不同函数的变量吗
好的-我试图让Python函数接受来自另外两个函数的变量。这可能吗Python:1个函数可以接受来自2个不同函数的变量吗,python,Python,好的-我试图让Python函数接受来自另外两个函数的变量。这可能吗 def calculate_deposit(total_cost, extras): deposit_percent = float(raw_input("Enter Deposit % (as a decimal) of Total Cost: ")) months_duration = float(raw_input("Enter the number of months client requires
def calculate_deposit(total_cost, extras):
deposit_percent = float(raw_input("Enter Deposit % (as a decimal) of Total Cost: "))
months_duration = float(raw_input("Enter the number of months client requires: "))
if deposit_percent >0:
IN HERE JUST SOME CALCULATIONS
else:
print "The total amount required is: ", total_cost
def rectangle(width, height, depth, thickness):
type = raw_input("Enter lowercase c for concrete: ")
if type == 'c':
output = IN HERE JUST COME CALCULATIONS
else:
return raw_input("Oops!, something went wrong")
print output + extras()
total_cost = calculate_deposit(output, extras)
def extras():
type = float(raw_input("Enter 1 for lights: "))
if type == 1:
light = 200
print "The cost of lights are: ", light
return light
else:
return raw_input("No extras entered")
下面是我试图做的一个示例(我已经简单地编写了原始代码,以便在这里输入)。希望你能理解我的想法。简而言之,我有一个矩形()调用Extras(),我希望矩形和Extras的输出被发送到Calculate\u Deposit()
这可能吗
def calculate_deposit(total_cost, extras):
deposit_percent = float(raw_input("Enter Deposit % (as a decimal) of Total Cost: "))
months_duration = float(raw_input("Enter the number of months client requires: "))
if deposit_percent >0:
IN HERE JUST SOME CALCULATIONS
else:
print "The total amount required is: ", total_cost
def rectangle(width, height, depth, thickness):
type = raw_input("Enter lowercase c for concrete: ")
if type == 'c':
output = IN HERE JUST COME CALCULATIONS
else:
return raw_input("Oops!, something went wrong")
print output + extras()
total_cost = calculate_deposit(output, extras)
def extras():
type = float(raw_input("Enter 1 for lights: "))
if type == 1:
light = 200
print "The cost of lights are: ", light
return light
else:
return raw_input("No extras entered")
在
矩形中
调用extras()
,然后只将函数extras
发送到计算存款()
。您希望发送extras()
调用的结果,而不是函数本身的引用。您可以进行微小更改并保存该值,在打印和进入计算押金
时参考该值
更改此项:
print output + extras()
total_cost = calculate_deposit(output, extras)
为此:
extra = extras()
print output + extra
total_cost = calculate_deposit(output, extra)
在
矩形中
调用extras()
,然后只将函数extras
发送到计算存款()
。您希望发送extras()
调用的结果,而不是函数本身的引用。您可以进行微小更改并保存该值,在打印和进入计算押金
时参考该值
更改此项:
print output + extras()
total_cost = calculate_deposit(output, extras)
为此:
extra = extras()
print output + extra
total_cost = calculate_deposit(output, extra)