python函数，用于根据列表中的有序项创建对

使用python，我试图创建一个对话对数据集，其中集合中的每一对都有speaker 1和speaker 2的后续响应。 对于上面的示例dat，我需要遍历列表，1）合并来自同一个说话人的句子（如果它们是后续的），2）按照下面的示例创建一对句子

输出：

dat = [(1,"hello"),(1,"how are you?"),(2,"I am doing well, thanks!"),
       (1,"Do anything fun this weekend?"),(2,"I mostly slept"),
       (2,"but I also played games"),(1,"That sounds fun")]

conv = []
ls, lm = dat[0]
for s, m in dat[1:]:
    if s == ls:
        lm += ' ' + m
    else:
        conv.append((ls, lm))
        ls, lm = s, m
else:
    conv.append((ls, lm))
    if conv[-1][0] == 1:
        conv.append((2, None))
output = tuple([(conv[i], conv[i+1]) for i in range(0,len(conv) - 1, 2)])

我如何编写一个函数，它接收像这样的顺序数据来创建对话对

((1,"hello how are you"),(2,"I am doing well, thanks!"))
((1,"Do anything fun this weekend?",(2,"I mostly slept but I also played games"))
((1,"That sounds fun"),(2,None))

输出：

dat = [(1,"hello"),(1,"how are you?"),(2,"I am doing well, thanks!"),
       (1,"Do anything fun this weekend?"),(2,"I mostly slept"),
       (2,"but I also played games"),(1,"That sounds fun")]

conv = []
ls, lm = dat[0]
for s, m in dat[1:]:
    if s == ls:
        lm += ' ' + m
    else:
        conv.append((ls, lm))
        ls, lm = s, m
else:
    conv.append((ls, lm))
    if conv[-1][0] == 1:
        conv.append((2, None))
output = tuple([(conv[i], conv[i+1]) for i in range(0,len(conv) - 1, 2)])

使用这段代码，希望能解决您的问题