Regex 提取两个变量之间的多行
我被困在一个代码中,我的要求是得到两个字符串变量之间的行,请建议一个正则表达式模式 输入:Regex 提取两个变量之间的多行,regex,powershell,Regex,Powershell,我被困在一个代码中,我的要求是得到两个字符串变量之间的行,请建议一个正则表达式模式 输入: Device Name: test Status: Completed Results: [PUSH_TERMLET] Action completed successfully... Pushing configuration file 'PUSH_TERMLET' for IDX 60504 with mechanism SSH ****** Enable Mode Results ****** sh
Device Name: test
Status: Completed
Results:
[PUSH_TERMLET] Action completed successfully...
Pushing configuration file 'PUSH_TERMLET' for IDX 60504 with mechanism SSH
****** Enable Mode Results ******
sh run | sec ip access-list standard customer_internal
ip access-list standard customer_internal
permit 204.79.49.116
permit 159.12.130.0 0.0.0.31
permit 10.108.30.0 0.0.0.255
permit 10.108.141.0 0.0.0.127
permit 10.108.172.0 0.0.0.255
permit 10.108.160.0 0.0.0.31
test#
输出:
permit 204.79.49.116
permit 159.12.130.0 0.0.0.31
permit 10.108.30.0 0.0.0.255
permit 10.108.141.0 0.0.0.127
permit 10.108.172.0 0.0.0.255
permit 10.108.160.0 0.0.0.31
这是我正在尝试的代码
$content = Get-Content -Path "TestACL.txt"
$device_list = $content | Select-String -Pattern "device name" -AllMatches
foreach($temp in $device_list) {
$temp.sp
$pattern = "(?<=$temp|permit)(.*)"
$content | Select-String -Pattern $pattern
}
除此之外,我还尝试了其他模式,它们都不适合我。你的正则表达式有点接近。让我们探讨一下这个选项
$Content = (Get-Content "C:\temp\TestACL.txt") -join ' '
$variable = "test#"
$Output = ($Content | Select-String -Pattern "(?:permit )(.*)(?= $($variable))").Matches.Value
?:permit将查找单词permit,包含空格,而?:将在匹配中包含它
?=test将包含单词test(包含空格),并且?=将匹配,但将其从主表达式后的结果中排除
.*将捕获第一个和最后一个条件之间的任何内容您应该通过添加-split'?=permit'@Drew来撤消连接谢谢您的回答!它对我有用。是否可以在正则表达式模式中将test用作变量。请suggest@KomalB我已经更新了我的答案,能够使用变量而不是测试