Sql server 2008 在计算列上使用触发器时，从字符串转换日期和/或时间时，转换失败 桌子 触发 错误

Msg 241，16级，状态1，第1行 从字符串转换日期和/或时间时，转换失败

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试试下面的insert语句，我觉得很好

insert into book_issue_return_details(
issued_date,
return_date, 
payed)
values
('16-05-2018','17-05-2018',0),
('07-05-2018','17-05-2018',0),
('01-05-2018','17-05-2018',0),
('17-05-2018','17-05-2018',0),
('01-04-2018','17-05-2018',0);

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首先，完成以下基本故障排除步骤：1。一次只插入一行，以查看特定行是否触发它；2.禁用触发器以查看触发器是否是问题所在。这是提问前应该做的基本故障排除您的触发器中有冗余代码，甚至没有必要-您可以将此计算放入计算列alsoyes，我尝试了此步骤，然后问了一个问题…您发现了什么？插入的四行中的哪一行导致错误？全部的触发器有什么区别吗？这个错误是因为日期格式，我在设置了日期格式后已经修复了它，然后请将它标记为答案。会帮助别人。谢谢

create trigger trforinsertpenalty
on book_issue_return_details
after insert
as
begin
    declare @value int
    select @value=for_days from book_issue_return_details;
    update book_issue_return_details 
        set penalty=case
        when for_days<'8' then 0
        when for_days='8' then 10
        when for_days='15' then 20
        when for_days='30' then 30 
        when for_days>'30' then 100
        end 
end

insert into book_issue_return_details(
issued_date,
return_date, 
payed)
values
('16-05-2018','17-05-2018',0),
('07-05-2018','17-05-2018',0),
('01-05-2018','17-05-2018',0),
('17-05-2018','17-05-2018',0),
('01-04-2018','17-05-2018',0);

 insert into book_issue_return_details(issued_date,return_date, payed)
 values('16-May-2018','17-May-2018',0),
       ('07-May-2018','17-May-2018',0),
       ('01-May-2018','17-May-2018',0),
       ('17-May-2018','17-May-2018',0),
       ('01-Apr-2018','17-May-2018',0);