Sql server 选择最高值，无论何时多次出现相同的值

我使用下面的代码从我的国家1-5中检索最高值，但是当有多个国家具有相同值时，该代码会呈现NULL。如何选择a）国家1-5的最高值，以及B）如果某些国家的值相同，则选择第一个具有该值的国家（从1开始）。 这是我使用的代码：

    , Risk AS(
 SELECT *,
        (SELECT MAX(v)
        FROM (
            VALUES  (Redflag.[country1]), 
                    (Redflag.[country2]), 
                    (Redflag.[country3]), 
                    (Redflag.[country4]), 
                    (Redflag.[country5])) AS value(v)
        ) AS highest_risk  
FROM Redflag

)

这就是我得到的：

SELECT 1 AS ID, 0.5 AS country1,  0 AS country2, 0.5 AS country3, 0 AS country4, 0 AS country5, NULL AS highest_risk
    UNION
   SELECT 2 AS ID, 0.5 AS country1,  0.5 AS country2, 2 AS country3, 0  AS country4, 0 AS country5,  2 AS highest_risk
    UNION
   SELECT 3 AS ID, 0  AS country1, 2  AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5,  2 AS highest_risk
    UNION
    SELECT 4 AS ID, 0 AS country1,  0 AS country2, 0 AS country3, 0  AS country4,  5 AS country5,  5 AS highest_risk
    UNION
   SELECT 5 AS ID, 0.5 AS country1,  0.5 AS country2, 3 AS country3, 3 AS country4, 0.5 AS country5,  NULL AS highest_risk
    UNION
   SELECT 6 AS ID,0 AS country1,  0 AS country2, 0 AS country3, 0.5 AS country4, 0.5 AS country5,  NULL AS highest_risk
    UNION
    SELECT 7 AS ID, 0 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5,  0.5 AS highest_risk
    UNION
  SELECT 8 AS ID, 0.5 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5, NULL AS highest_risk
    UNION
  SELECT 9 AS ID, 0.5 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 4 AS country5,  4 AS highest_risk

我需要这样：

SELECT 1 AS ID, 0.5 AS country1,  0 AS country2, 0.5 AS country3, 0 AS country4, 0 AS country5,  0.5 AS highest_risk
        UNION
       SELECT 2 AS ID, 0.5 AS country1,  0.5 AS country2, 2 AS country3, 0  AS country4, 0 AS country5,  2 AS highest_risk
        UNION
       SELECT 3 AS ID, 0  AS country1, 2  AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5,  2 AS highest_risk
        UNION
        SELECT 4 AS ID, 0 AS country1,  0 AS country2, 0 AS country3, 0  AS country4,  5 AS country5,  5 AS highest_risk
        UNION
       SELECT 5 AS ID, 0.5 AS country1,  0.5 AS country2, 3 AS country3, 3 AS country4, 0.5 AS country5,  3 AS highest_risk
        UNION
       SELECT 6 AS ID,0 AS country1,  0 AS country2, 0 AS country3, 0.5 AS country4, 0.5 AS country5,  0.5 AS highest_risk
        UNION
        SELECT 7 AS ID, 0 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5,  0.5 AS highest_risk
        UNION
      SELECT 8 AS ID, 0.5 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 0.5 AS country5,  0.5 AS highest_risk
        UNION
      SELECT 9 AS ID, 0.5 AS country1,  0.5 AS country2, 0.5 AS country3, 0.5 AS country4, 4 AS country5,  4 AS highest_risk

---

最简单的方法是什么？

类似的方法。“最大风险”列包含a）国家1-5的最高值。“min_country”列包含b）如果某些国家具有相同的值，则选择第一个具有该值的国家（从1开始）

资料

质疑

输出

id  country1    country2    country3    country4    country5    min_country max_risk
1   0.5         0.0         0.5         0.0         0.0         1           0.5
2   0.5         0.5         2.0         0.0         0.0         3           2.0
3   0.0         2.0         0.5         0.5         0.5         2           2.0
4   0.0         0.0         0.0         0.0         5.0         5           5.0
5   0.5         0.5         3.0         3.0         0.5         3           3.0
6   0.0         0.0         0.0         0.5         0.5         4           0.5
7   0.0         0.5         0.5         0.5         0.5         2           0.5
8   0.5         0.5         0.5         0.5         0.5         1           0.5
9   0.5         0.5         0.5         0.5         4.0         5           4.0

---

您的查询应该满足您的要求。可能您没有针对这个精确的样本数据运行这个精确的查询。它是CTE的一部分，是否应该更接近数据源？。结果是您希望与现有查询一起使用的结果。

with country_cte(id, country1, country2, country3, country4, country5, v_n, v_v, rn) as (
    select *, row_number() over (partition by id order by v.v desc, v.n) rn
    from
      #redflag r
      cross apply
     (values  (1, r.[country1]), (2, r.[country2]), 
              (3, r.[country3]), (4, r.[country4]), 
              (5, r.[country5])) AS v(n, v))
select id, country1, country2, country3, country4, country5, v_n min_country, v_v max_risk
from country_cte 
where rn=1;

id  country1    country2    country3    country4    country5    min_country max_risk
1   0.5         0.0         0.5         0.0         0.0         1           0.5
2   0.5         0.5         2.0         0.0         0.0         3           2.0
3   0.0         2.0         0.5         0.5         0.5         2           2.0
4   0.0         0.0         0.0         0.0         5.0         5           5.0
5   0.5         0.5         3.0         3.0         0.5         3           3.0
6   0.0         0.0         0.0         0.5         0.5         4           0.5
7   0.0         0.5         0.5         0.5         0.5         2           0.5
8   0.5         0.5         0.5         0.5         0.5         1           0.5
9   0.5         0.5         0.5         0.5         4.0         5           4.0