SQL:Presto中的交叉表等价物
我有一张这样的桌子:SQL:Presto中的交叉表等价物,sql,pivot,crosstab,presto,Sql,Pivot,Crosstab,Presto,我有一张这样的桌子: shop number work station accept create no.of entries 1 123 Maintain Arrive 2019-10-11 0:00:00 2019-10-11 0:00:00 1 1 123 Maintain WorkA 2019-10-11 0:00:00 2019-10-11 0:00:00 1 1 123 Maintain WorkB 2019-10-1
shop number work station accept create no.of entries
1 123 Maintain Arrive 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 123 Maintain WorkA 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 123 Maintain WorkB 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job Arrive 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job WorkC 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job WorkD 2019-10-11 0:00:00 2019-10-11 0:00:00 1
shop number work arrival_accept arrival_create worka_accept worka_create workb_accept workb_create workc_accept workc_create workd_accept workd_create no.of entries
1 123 Maintain 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 1
我想将其转换为如下所示:
shop number work station accept create no.of entries
1 123 Maintain Arrive 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 123 Maintain WorkA 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 123 Maintain WorkB 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job Arrive 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job WorkC 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job WorkD 2019-10-11 0:00:00 2019-10-11 0:00:00 1
shop number work arrival_accept arrival_create worka_accept worka_create workb_accept workb_create workc_accept workc_create workd_accept workd_create no.of entries
1 123 Maintain 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 1
1 1234 Job 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 2019-10-11 0:00:00 1
我知道在博士后我们可以使用交叉表来实现这一点。然而,我无法用普雷斯托做到这一点。有什么方法可以做到这一点吗?您可以使用条件聚合。如果您知道所有电台,它看起来像:
select shop, number, work,
max(case when station = 'Arrive' then accept end) as arrive_accept,
max(case when station = 'Arrive' then create end) as arrive_create,
max(case when station = 'WorkA' then accept end) as workA_accept,
max(case when station = 'WorkA' then create end) as workA_create,
. . . -- and so on for the rest of the stations
from t
group by shop, number, work;
否则,您将需要动态构造查询,以执行几乎相同的操作,但列数是可变的