Sql 基于列名确定索引

是否有任何方法将列名与索引中的列名相匹配

例如，让我们假设index1使用列名称、年龄、地址，index2使用（在同一个表中）名称、年龄

如果我将name、age和表名传递给存储的proc，我应该编写什么查询来返回index2而不是index1

我遇到了许多关于如何使用索引和表名列出列的示例，如：

但是仍然无法为我的使用编写sql查询

任何帮助都将不胜感激

多谢各位

（这是针对Microsoft sql server 2008-2012的）

这是我写的，它没有正常工作，因此问题

select index1.name,sys.tables.name, Stuff((SELECT ',' + sys.columns.name AS [text()]
FROM
(
     select sys.columns.name
     from sys.columns
     inner join sys.index_columns On sys.index_columns.index_column_id=sys.columns.column_id
     inner join sys.indexes on sys.indexes.index_id=sys.index_columns.index_id 
     where sys.indexes.index_id=index1.index_id
) x
For XML PATH (''), type ).value('(./text())[1]','NVARCHAR(MAX)'),1,1,'') As coLName
from sys.indexes as index1 
inner join sys.tables on sys.tables.object_id=index1.object_id
inner join sys.index_columns On index1.index_id=sys.index_columns.index_id  AND sys.index_columns.object_id = sys.tables.object_id
inner join sys.columns on sys.columns.column_id=sys.index_columns.column_id And sys.columns.object_id=sys.tables.object_id
where sys.tables.name=TABLE_NAME

---

您可以使用以下命令尝试此查询：

在第二个场景中，无论顺序如何，都要指定列和空间

DECLARE @searchIndex nvarchar(100) = '  age, name' ,
        @tableName nvarchar (100) = 'your_tableName'       
;WITH ParsSearchIndex AS
 (
  SELECT SUBSTRING(@searchIndex , 0 , CHARINDEX ( ',' , @searchIndex )) AS val ,
         CAST(STUFF (@searchIndex + ',' , 1, CHARINDEX( ',', @searchIndex), '') AS nvarchar (100 )) AS stval        
  UNION ALL
  SELECT LTRIM(SUBSTRING (stval , 0, CHARINDEX( ',', stval))),
         CAST(STUFF (stval , 1, CHARINDEX( ',' , stval ), '' ) AS nvarchar(100 ))        
  FROM ParsSearchIndex
  WHERE stval != ''
  ), max_ParsSearchIndex AS
 (
  SELECT val, COUNT(*) OVER() AS cnt
  FROM ParsSearchIndex
  WHERE val != ''
  ), cte AS
 (
  SELECT i.name AS index_name, c.name , ic .is_included_column,
         MAX(ic .index_column_id) OVER( PARTITION BY i. index_id) AS maxIndex_column_id
  FROM sys.indexes i LEFT JOIN sys. index_columns ic ON i.object_id = ic.object_id AND i.index_id = ic.index_id
                     LEFT JOIN sys. columns c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
  WHERE i.object_id = OBJECT_ID(@tableName )
  ), cte2 AS
 (
  SELECT c2.index_name , COUNT (*) AS cnt, c2. maxIndex_column_id,
    STUFF((SELECT ',' + c .name
           FROM cte c
           WHERE c .index_name = c2 .index_name        
  FOR XML PATH , TYPE ).value( '.[1]', 'nvarchar(max)'), 1 , 1, '') [columns]
  FROM cte c2
  WHERE c2.is_included_column != 1 AND EXISTS (
                         SELECT 1
                         FROM max_ParsSearchIndex p
                         WHERE c2 .name = p .val AND p .cnt = c2.maxIndex_column_id
                         )
  GROUP BY c2 .index_name, c2. maxIndex_column_id
  )
  SELECT index_name, [columns]
  FROM cte2
  WHERE cnt = maxIndex_column_id

---

您可以使用以下命令尝试此查询：

在第二个场景中，无论顺序如何，都要指定列和空间

DECLARE @searchIndex nvarchar(100) = '  age, name' ,
        @tableName nvarchar (100) = 'your_tableName'       
;WITH ParsSearchIndex AS
 (
  SELECT SUBSTRING(@searchIndex , 0 , CHARINDEX ( ',' , @searchIndex )) AS val ,
         CAST(STUFF (@searchIndex + ',' , 1, CHARINDEX( ',', @searchIndex), '') AS nvarchar (100 )) AS stval        
  UNION ALL
  SELECT LTRIM(SUBSTRING (stval , 0, CHARINDEX( ',', stval))),
         CAST(STUFF (stval , 1, CHARINDEX( ',' , stval ), '' ) AS nvarchar(100 ))        
  FROM ParsSearchIndex
  WHERE stval != ''
  ), max_ParsSearchIndex AS
 (
  SELECT val, COUNT(*) OVER() AS cnt
  FROM ParsSearchIndex
  WHERE val != ''
  ), cte AS
 (
  SELECT i.name AS index_name, c.name , ic .is_included_column,
         MAX(ic .index_column_id) OVER( PARTITION BY i. index_id) AS maxIndex_column_id
  FROM sys.indexes i LEFT JOIN sys. index_columns ic ON i.object_id = ic.object_id AND i.index_id = ic.index_id
                     LEFT JOIN sys. columns c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
  WHERE i.object_id = OBJECT_ID(@tableName )
  ), cte2 AS
 (
  SELECT c2.index_name , COUNT (*) AS cnt, c2. maxIndex_column_id,
    STUFF((SELECT ',' + c .name
           FROM cte c
           WHERE c .index_name = c2 .index_name        
  FOR XML PATH , TYPE ).value( '.[1]', 'nvarchar(max)'), 1 , 1, '') [columns]
  FROM cte c2
  WHERE c2.is_included_column != 1 AND EXISTS (
                         SELECT 1
                         FROM max_ParsSearchIndex p
                         WHERE c2 .name = p .val AND p .cnt = c2.maxIndex_column_id
                         )
  GROUP BY c2 .index_name, c2. maxIndex_column_id
  )
  SELECT index_name, [columns]
  FROM cte2
  WHERE cnt = maxIndex_column_id

这对我有用

DECLARE @searchIndex nvarchar(100) = 'age,name',
        @schemeName nvarchar(100) = 'dbo',
        @tableName nvarchar(100) = 'tableName'

SELECT
    name
FROM (SELECT
    indexes.name,
    (SELECT
            c1.name + ','
    FROM sys.schemas s1
    INNER JOIN sys.tables t1
        ON s1.schema_id = t1.schema_id
        AND tables.object_id = t1.object_id
    INNER JOIN sys.columns c1
        ON t1.object_id = c1.object_id
    INNER JOIN sys.indexes i1
        ON t1.object_id = i1.object_id
        AND indexes.index_id = i1.index_id
    INNER JOIN sys.index_columns ic1
        ON t1.object_id = ic1.object_id
        AND i1.index_id = ic1.index_id
        AND c1.column_id = ic1.column_id
    WHERE schemas.schema_id = s1.schema_id
    ORDER BY c1.name
    FOR xml PATH (''))
    AS colName
FROM sys.schemas
INNER JOIN sys.tables
    ON schemas.schema_id = tables.schema_id
    AND tables.name = @tableName
INNER JOIN sys.indexes
    ON tables.object_id = indexes.object_id
WHERE schemas.name = @schemeName) A
WHERE A.colName = @searchIndex + ',' 

这对我有用

DECLARE @searchIndex nvarchar(100) = 'age,name',
        @schemeName nvarchar(100) = 'dbo',
        @tableName nvarchar(100) = 'tableName'

SELECT
    name
FROM (SELECT
    indexes.name,
    (SELECT
            c1.name + ','
    FROM sys.schemas s1
    INNER JOIN sys.tables t1
        ON s1.schema_id = t1.schema_id
        AND tables.object_id = t1.object_id
    INNER JOIN sys.columns c1
        ON t1.object_id = c1.object_id
    INNER JOIN sys.indexes i1
        ON t1.object_id = i1.object_id
        AND indexes.index_id = i1.index_id
    INNER JOIN sys.index_columns ic1
        ON t1.object_id = ic1.object_id
        AND i1.index_id = ic1.index_id
        AND c1.column_id = ic1.column_id
    WHERE schemas.schema_id = s1.schema_id
    ORDER BY c1.name
    FOR xml PATH (''))
    AS colName
FROM sys.schemas
INNER JOIN sys.tables
    ON schemas.schema_id = tables.schema_id
    AND tables.name = @tableName
INNER JOIN sys.indexes
    ON tables.object_id = indexes.object_id
WHERE schemas.name = @schemeName) A
WHERE A.colName = @searchIndex + ',' 

---

---

您使用哪种RDBMS？这是什么SQL产品？与键不同，in-SQL索引几乎完全是特定于实现的，因此您必须知道您使用的是哪种类型的SQL才能编写类似的内容。对不起，这是针对Microsoft SQL server 2008-2012的，您使用的是哪种RDBMS？这是用于什么SQL产品？与键不同，in-SQL索引几乎完全是特定于实现的，因此您必须知道您使用的SQL类型才能编写类似的内容。抱歉，这是针对Microsoft SQL server 2008-2012的。谢谢，这完成了任务。我指定列名的顺序是否重要（例如，如果我指定了年龄，命名此项不返回任何内容。我想我必须按字母顺序指定列。很抱歉，您的第二个解决方案不适用于无序列，即年龄、名称。我试着通过你的第二个查询，在cte2中，它没有带来所有的索引，cnt不等于maxIndex_column_Id。我本来会粘贴一个屏幕截图，但网站阻止我这样做。如果我能提供更多信息，请告诉我。我的问题是，我的索引中包含了非键列，而我只是在查询时指定了键列，我必须添加一个额外的条件ic.key_ordinal=0以确保sql只查询键列，并且它现在工作正常。谢谢谢谢，这就完成了。我指定列名的顺序有关系吗？例如，如果我指定了年龄，命名这个将不返回任何内容。我想我必须按字母顺序指定列。很抱歉，您的第二个解决方案不适用于无序列，即年龄、名称。我试着通过你的第二个查询，在cte2中，它没有带来所有的索引，cnt不等于maxIndex_column_Id。我本来会粘贴一个屏幕截图，但网站阻止我这样做。如果我能提供更多信息，请告诉我。我的问题是，我的索引中包含了非键列，而我只是在查询时指定了键列，我必须添加一个额外的条件ic.key_ordinal=0以确保sql只查询键列，并且它现在工作正常。谢谢，我指定列名的顺序有关系吗？因为这对年龄、名称不返回任何结果。此查询按ic1.index\u column\u id对结果进行排序。因此排序很重要。这假设age、name和name、age是您可以查找的两个不同索引。是的，我想我将按字母顺序指定列名，因为上面的查询按字母顺序返回列名。再次感谢。如果列的顺序不重要，只需将顺序改为c1.name，并确保列在@searchIndex中按字母顺序排列。我指定列名的顺序是否重要，因为这不会返回任何年龄，名称此查询按ic1.index\u column\u id对结果进行排序。因此排序很重要。这假设age、name和name、age是您可以查找的两个不同索引。是的，我想我将按字母顺序指定列名，因为上面的查询按字母顺序返回列名。再次感谢。如果列的顺序不重要，只需将顺序改为c1.name，并确保列在@searchIndex中按字母顺序排列即可。