如何在sql中的一列中插入父记录和子记录？

我需要将一列中的父子记录放到另一个具有该ID的表中。及 我试过这个：

select parent.Parent,child1.child1,Child2.child2 
from parent 
join Child1 on child1.ParentIdId=parent.ParentID 
join Child2  on child1.child1Id=child2.child1Id` 

Create table parent (ParentID int, Parent varchar(10))

Create table Child1 (child1Id int, child1 varchar(10), ParentIdId int)
Create table Child2 (child2Id int, child2 varchar(10), child1Id int)


insert into parent values(10,'Sony'),(20,'Apple'),(30,'HTC'),(40,'Nexus')
insert into Child1 values(100,'Sony1',10),(200,'Sony2',10),(300,'Apple1',20),(400,'Apple2',20),(500,'HTC1',30),(600,'HTC2',30),
(700,'Nexus1',40),(800,'Nexus2',40)

insert into Child2 values(1000,'Sony11',100),(2000,'Sony22',100),(3000,'Apple11',200),(4000,'Apple22',200),(5000,'HTC11',300),(6000,'HTC22',300),
(7000,'Nexus11',400),(8000,'Nexus22',400)

我需要的输出：

Ids Products    Parents
10  Sony        null
20  Apple       null
30  HTC         null
40  Nexus       null
100 Sony1       10
200 Sony2       10
300 Apple1      20
400 Apple2      20
500 HTC1        30
600 HTC2        30
700 Nexus2      40
800 Nexus2      40
1000    Sony11  100
2000    Sony22  100
3000    Apple11 200
4000    Apple22 200
5000    HTC11   300
6000    HTC22   300
7000    Nexus11 400
8000    Nexus22 400

---

您可能必须在下面3种不同的select查询中执行此操作

SELECT ParentIds as Ids,
       Parent as Products,
       CAST(NULL AS INT) AS Parent
INTO #Product
FROM Parent
UNION ALL
SELECT child1.child1id,
       Child1.child1,
       Child1.ParentId 
FROM parent 
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID 
UNION ALL
SELECT Child2.Child2Id,child2.child2,Child2.child1Id 
FROM parent 
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID 
INNER JOIN Child2  on child1.child1Id=child2.child1Id` 

---

您可能必须在下面3种不同的select查询中执行此操作

SELECT ParentIds as Ids,
       Parent as Products,
       CAST(NULL AS INT) AS Parent
INTO #Product
FROM Parent
UNION ALL
SELECT child1.child1id,
       Child1.child1,
       Child1.ParentId 
FROM parent 
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID 
UNION ALL
SELECT Child2.Child2Id,child2.child2,Child2.child1Id 
FROM parent 
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID 
INNER JOIN Child2  on child1.child1Id=child2.child1Id` 

---

我认为对于您的示例，“简单联合”就足够了，但我认为您正在寻找递归cte，如下所示：

;with cte (Child, nam, parent) as
(
    select * from child2
    union all
    select * from child1
    union all
    select *, null as Parent from parent
) 
, cte2 as
(
    select *, 0 as Levl from cte where parent is null

    union all

    select c1.*, c2.Levl + 1 as Levl from cte2 c2 join cte c1
        on c2.child = c1.parent
)
select * from cte2
order by levl

---

我添加了Levl只是为了理解层次结构

我认为对于您的示例，简单的联合就足够了，但我认为您正在寻找递归cte，如下所示：

;with cte (Child, nam, parent) as
(
    select * from child2
    union all
    select * from child1
    union all
    select *, null as Parent from parent
) 
, cte2 as
(
    select *, 0 as Levl from cte where parent is null

    union all

    select c1.*, c2.Levl + 1 as Levl from cte2 c2 join cte c1
        on c2.child = c1.parent
)
select * from cte2
order by levl

---

我添加Levl只是为了理解层次结构，而不使用UNIONALL和多个select语句

SELECT COALESCE(parent.ParentID, Child1.child1id, Child2.child2id),
       COALESCE(Child2.child2, Child1.child1, parent.Parent), 
       COALESCE( Child1.ParentIdId, Child2.child1id) FROM parent
FULL JOIN Child1 on 1 = 2
FULL JOIN Child2 on 1 = 2

---

不使用union all和多个select语句

SELECT COALESCE(parent.ParentID, Child1.child1id, Child2.child2id),
       COALESCE(Child2.child2, Child1.child1, parent.Parent), 
       COALESCE( Child1.ParentIdId, Child2.child1id) FROM parent
FULL JOIN Child1 on 1 = 2
FULL JOIN Child2 on 1 = 2

---

谢谢你的回答@saj。。如果可能，不使用“联合所有”选项，请在@saj.上搜索您的答案。。如果可能，不使用“联合所有”option@Meline这就是你的意思吗？谢谢你。但是1=2和1=2是什么呢。我可以用身份证that@Meline这就是你的意思吗？谢谢你。但是1=2和1=2是什么呢。我可以用身份证