Warning: file_get_contents(/data/phpspider/zhask/data//catemap/5/sql/84.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Sql 时钟相关查询逻辑_Sql_Sql Server_Database - Fatal编程技术网

Sql 时钟相关查询逻辑

Sql 时钟相关查询逻辑,sql,sql-server,database,Sql,Sql Server,Database,我真的需要一些帮助来解决以下场景的查询 tblStaff | ESID | EID | FName | LName | +------+-----+-------+--------+ | 1 | 10 | Joe | Smith | | 2 | 10 | Dan | Jones | | 3 | 10 | Rick | Brown | | 4 | 10 | Pete | Miller | | 5 | 10 | Ken | White

我真的需要一些帮助来解决以下场景的查询

tblStaff

| ESID | EID | FName | LName  |
+------+-----+-------+--------+
| 1    | 10  | Joe   | Smith  |
| 2    | 10  | Dan   | Jones  |
| 3    | 10  | Rick  | Brown  |
| 4    | 10  | Pete  | Miller |
| 5    | 10  | Ken   | White  |

tblStaffTime

| TCID | EID | ESID | DTIn                    | DTOut                   |
+------+-----+------+-------------------------+-------------------------+
| 1    | 10  | 1    | 2013-09-22 08:00:00.000 | 2013-09-22 17:00:00.000 |
| 2    | 10  | 1    | 2013-09-23 08:00:00.000 | NULL                    |
| 3    | 10  | 2    | 2013-09-23 08:00:00.000 | 2013-09-23 17:00:00.000 |
| 4    | 10  | 3    | 2013-09-22 08:00:00.000 | 2013-09-22 17:00:00.000 |
| 5    | 10  | 3    | 2013-09-23 08:00:00.000 | NULL                    |
我的目标是: 列出EID等于10的所有人,其中最近的DTOut不为null,或者他们在tblStaffTime中根本没有此EID的记录。换言之,EID等于10的所有员工都有一份名单,上面列出了谁准备好登记

到目前为止,我的SQL:

SELECT tblStaff.ESID AS ID,tblStaff.SFirst + CHAR(32) + tblStaff.SLast AS StaffName
FROM tblStaff
LEFT JOIN tblStaffTime ON tblStaff.ESID = tblStaffTime.ESID
WHERE tblStaff.ESID = (SELECT ESID FROM tblStaffTime WHERE EID = '10' AND ESID = tblStaffTime.ESID AND DTIn IS NOT NULL AND DTOut IS NOT NULL)
UNION ALL
SELECT tblStaff.ESID AS ID,tblStaff.SFirst + CHAR(32) + tblStaff.SLast AS StaffName
FROM tblStaff
LEFT JOIN tblStaffTime ON tblStaff.ESID = tblStaffTime.ESID
WHERE NOT EXISTS (SELECT 1 FROM tblStaffTime WHERE tblStaffTime.ESID = tblStaff.ESID) AND tblStaff.EID = '10'
ORDER BY tblStaff.SFirst + CHAR(32) + tblStaff.SLast
期望输出:

| ESID | StaffName   |
+------+-------------+
| 2    | Dan Jones   |
| 5    | Ken White   |
| 4    | Pete Miller |

我所在的工会南部解决了我的问题,那就是让那些没有参加EID的员工来上班。我的主要问题是我的北方。我需要获取最新的DTIn,并查看该记录的DTOut是否为null,以确定它们是否应被列为已准备好输入时钟。我敢肯定,这些SQL都可以写得更干净。我现在就交给专家们处理

如果您使用的是SQL Server 2005或更高版本,则可以使用窗口函数来帮助完成此操作

左侧外部联接有助于包括没有记录的人,而order by DTIn允许我们在有记录时选择最新的时间记录

With x as (
    Select
        s.ESID,
        s.EID,
        s.FName,
        s.LName,
        t.DTIn,
        t.DTOut,
        row_number() over (partition by s.ESID, s.EID order by DTIn Desc) rn
    From
        tblStaff s
            Left Outer Join
        tblStaffTime t
            On s.ESID = t.ESID and s.EID = t.EID
)
Select
    x.ESID,
    x.EID,
    x.FName,
    x.LName
From
    x
Where
    x.EID = 10 And
    x.rn = 1 And (
      x.DTIn Is Null Or -- no time records
      x.DTOut IS Not Null -- latest time record has not null clock out
    )

与论坛网站不同,我们不使用“感谢”或“感谢任何帮助”或签名。请参阅“。测试数据的预期结果将非常有用