String 从PowerShell中的绝对路径获取相对路径 问题

String 从PowerShell中的绝对路径获取相对路径 问题,string,powershell,path,relative-path,absolute-path,String,Powershell,Path,Relative Path,Absolute Path,您有一个绝对路径,但希望它相对于另一个路径 例如: P:/SO/data/database.txt --> Now we want the filename to be relative to: P:/SO/team/lists/ ../../data/database.txt 我已经发现堆栈溢出 问题 一个答案链接到一个,但这个答案对我不起作用。使用Set/Get Location的技巧需要路径存在。解决方案 我从PHP中找到了一个答案: 这是我到PowerShell的端口: <

您有一个绝对路径,但希望它相对于另一个路径

例如:

P:/SO/data/database.txt

--> Now we want the filename to be relative to: P:/SO/team/lists/
../../data/database.txt
我已经发现堆栈溢出 问题

一个答案链接到一个,但这个答案对我不起作用。使用
Set/Get Location
的技巧需要路径存在。

解决方案 我从PHP中找到了一个答案:

这是我到PowerShell的端口:

<# This is probably not the best code I've ever written, but
   I think it should be readable for most (advanced) users.

   I will wrap this function into a Cmdlet when I have time to do it.
   Feel free to edit this answer and improve it!
#>
function getRelativePath([string]$from, [string]$to, [string]$joinSlash='/') {

    $from = $from -replace "(\\)", "/";
    $to = $to -replace "(\\)", "/";

    $fromArr = New-Object System.Collections.ArrayList;
    $fromArr.AddRange($from.Split("/"));

    $relPath = New-Object System.Collections.ArrayList;
    $relPath.AddRange($to.Split("/"));


    $toArr = New-Object System.Collections.ArrayList;
    $toArr.AddRange($to.Split("/"));

    for ($i=0; $i -lt $fromArr.Count; $i++) {
        $dir = $fromArr[$i];

        # Find first non-matching directory
        if ($dir.Equals($toArr[$i])) {
            # ignore this directory
            $relPath.RemoveAt(0);
        }
        else {
            # Get number of remaining directories to $from
            $remaining = $fromArr.Count - $i;
            if ($remaining -gt 1) {
                # Add traversals up to first matching directory
                $padLength = ($relPath.Count + $remaining - 1);

                # Emulate array_pad() from PHP
                for (; $relPath.Count -ne ($padLength);) {
                    $relPath.Insert(0, "..");
                }
                break;
            }
            else {
                $relPath[0] = "./" + $relPath[0];
            }
        }
    }
    return $relPath -Join $joinSlash;
}

老实说,我更喜欢这个解决方案:@MikaëlMayer您的链接只包含Bash解决方案,因此它们无法与我的相比。
getRelativePath -From "P:/SO/team/lists/" -To "P:/SO/data/database.txt";
--> ../../data/database.txt

getRelativePath -From "C:/Windows/System32/" -To "C:/Users/ComFreek/Desktop/SO.txt";
--> ../../Users/ComFreek/Desktop/SO.txt