如何调用swift函数

我有一个功能：

func chatAttachmentService(chatAttachmentService: QMChatAttachmentService, didChangeLoadingProgress progress: CGFloat, forChatAttachment attachment: QBChatAttachment)

func testFunction(chatAttachmentService: String, didChangeLoadingProgress progress: String, forChatAttachment attachment: String) {

    //Your code
}

我想在我的文件中调用它：

self.chatAttachmentService(chatAttachmentService, progress, attachment)

---

我知道这是个疯狂的问题，但Xcode在键入函数名时并没有给我提示，我不知道如何正确调用它…

例如，您可以这样做：

testFunction("", didChangeLoadingProgress: "", forChatAttachment: "")

以下是示例函数：

func chatAttachmentService(chatAttachmentService: QMChatAttachmentService, didChangeLoadingProgress progress: CGFloat, forChatAttachment attachment: QBChatAttachment)

func testFunction(chatAttachmentService: String, didChangeLoadingProgress progress: String, forChatAttachment attachment: String) {

    //Your code
}

你可以这样称呼它：

testFunction("", didChangeLoadingProgress: "", forChatAttachment: "")

---

例如，您可以这样做：

testFunction("", didChangeLoadingProgress: "", forChatAttachment: "")

以下是示例函数：

func chatAttachmentService(chatAttachmentService: QMChatAttachmentService, didChangeLoadingProgress progress: CGFloat, forChatAttachment attachment: QBChatAttachment)

func testFunction(chatAttachmentService: String, didChangeLoadingProgress progress: String, forChatAttachment attachment: String) {

    //Your code
}

你可以这样称呼它：

testFunction("", didChangeLoadingProgress: "", forChatAttachment: "")

---

你是说Xcode智能不起作用？然后退出Xcode并重新启动它。尝试重新启动Xcode并清理生成文件夹。尽管请注意，调用函数时会忽略第一个参数名，除非它有显式的外部参数名。@JigarTarsariya是的，你是说Xcode智能无法工作？然后退出Xcode并重新启动它。尝试重新启动Xcode并清理生成文件夹。尽管请注意，调用函数时会忽略第一个参数名，除非它有显式的外部参数名。@JigarTarsariya是的