Tsql 基于另一个表填充Id

我有下表：

上述示例数据如下所示：

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')

select
*
from    @years

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')


;with cte as
(
select  dateadd(day, nbr - 1, (select min(dYearStartDate) from @years)) CalendarDate
from    ( select    row_number() over ( order by c.object_id ) as nbr
          from      sys.columns c
        ) nbrs
where   nbr - 1 <= datediff(day, (select min(dYearStartDate) from @years), (select max(dYearStartDate) from @years))
)
,   months as (
select
eomonth(CalendarDate)   EndOfMonth
from    cte
group by eomonth(CalendarDate)
)

select
*
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,   isnull(idYear,lag(idYear) over (order by EndOfMonth))   idYear
,   (select idYear from @years where year(dYearStartDate) = year(EndOfMonth))   idYear
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,       iif(idYear is null,(select idYear from LeadDateAdded where EndOfMonth between dYearStartDate and dYearEndDate),idYear)  idYear
from    months m
left join LeadDateAdded y   on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

请注意，其中idYear=1的开始日期是该月的结束日期。我以这种方式提供了示例数据，因为它在我的实际表中是完全一样的

然后，我使用以下脚本为这两个月之间的所有时段生成每个月末：

;with cte as
(
select  dateadd(day, nbr - 1, (select min(dYearStartDate) from @years)) CalendarDate
from    ( select    row_number() over ( order by c.object_id ) as nbr
          from      sys.columns c
        ) nbrs
where   nbr - 1 <= datediff(day, (select min(dYearStartDate) from @years), (select max(dYearStartDate) from @years))
)
,   months as (
select
eomonth(CalendarDate)   EndOfMonth
from    cte
group by eomonth(CalendarDate)
)

select
*
from    months

以上给出了以下结果：

我如何操作它，使其看起来如下所示：

我试过排名、分数和行数，但没有一个能给出我需要的结果

非常感谢您的帮助

编辑

我已将上面的选择更改为以下内容：

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')

select
*
from    @years

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')


;with cte as
(
select  dateadd(day, nbr - 1, (select min(dYearStartDate) from @years)) CalendarDate
from    ( select    row_number() over ( order by c.object_id ) as nbr
          from      sys.columns c
        ) nbrs
where   nbr - 1 <= datediff(day, (select min(dYearStartDate) from @years), (select max(dYearStartDate) from @years))
)
,   months as (
select
eomonth(CalendarDate)   EndOfMonth
from    cte
group by eomonth(CalendarDate)
)

select
*
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,   isnull(idYear,lag(idYear) over (order by EndOfMonth))   idYear
,   (select idYear from @years where year(dYearStartDate) = year(EndOfMonth))   idYear
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,       iif(idYear is null,(select idYear from LeadDateAdded where EndOfMonth between dYearStartDate and dYearEndDate),idYear)  idYear
from    months m
left join LeadDateAdded y   on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

但可以看出，这与我的预期结果不符：

---

您可以尝试通过加入@years表来获取每年的信息YEAR@years.dYearStartDate和YEARmonth.EndOfMonth，就像这样：

select a.EndOfMonth, b.idYear, b.cYearDescription, b.dYearStartDate
 from (
    select year(m.EndOfMonth) curYear, *
       from months m
     left join @years y  
       on  eomonth(dYearStartDate) = EndOfMonth) a
   inner join (select year(dYearStartDate) curYear, * from @years) b
     on a.curYear = b.curYear
   order by EndOfMonth

---

我能解决这个问题的唯一方法是使用LEAD在我的表中添加一个结束日期，这很有效

鉴于上述情况，我可以通过以下方式查询这些日期之间的时间：

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')

select
*
from    @years

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')


;with cte as
(
select  dateadd(day, nbr - 1, (select min(dYearStartDate) from @years)) CalendarDate
from    ( select    row_number() over ( order by c.object_id ) as nbr
          from      sys.columns c
        ) nbrs
where   nbr - 1 <= datediff(day, (select min(dYearStartDate) from @years), (select max(dYearStartDate) from @years))
)
,   months as (
select
eomonth(CalendarDate)   EndOfMonth
from    cte
group by eomonth(CalendarDate)
)

select
*
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,   isnull(idYear,lag(idYear) over (order by EndOfMonth))   idYear
,   (select idYear from @years where year(dYearStartDate) = year(EndOfMonth))   idYear
from    months m
left join @years y  on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

select
*
,       iif(idYear is null,(select idYear from LeadDateAdded where EndOfMonth between dYearStartDate and dYearEndDate),idYear)  idYear
from    months m
left join LeadDateAdded y   on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

完整的最终代码如下所示：

declare @years table (idYear int primary key identity, cYearDescription varchar(20), dYearStartDate datetime)

insert into @years (cYearDescription,dYearStartDate) values
    ('Year 1','2014-08-31')
,   ('Year 2','2015-07-01')
,   ('Year 3','2016-07-01')
,   ('Year 4','2017-07-01')
,   ('Year 5','2018-07-01')
,   ('Year 6','2019-07-01')
,   ('Year 7','2020-07-01')


;with cte as
(
select  dateadd(day, nbr - 1, (select min(dYearStartDate) from @years)) CalendarDate
from    ( select    row_number() over ( order by c.object_id ) as nbr
          from      sys.columns c
        ) nbrs
where   nbr - 1 <= datediff(day, (select min(dYearStartDate) from @years), (select max(dYearStartDate) from @years))
)
,   months as (
select
eomonth(CalendarDate)   EndOfMonth
from    cte
group by eomonth(CalendarDate)
)
,   Years as (
select
    idYear
,   cYearDescription
,   dYearStartDate
,   cast(lead(eomonth(dYearStartDate)) over (order by idYear) as datetime)  dYearEndDate
from    @years
)

select
*
,       iif(idYear is null,(select idYear from Years where EndOfMonth between dYearStartDate and dYearEndDate),idYear)  idYear
from    months m
left join Years y   on  eomonth(dYearStartDate) = EndOfMonth
order by EndOfMonth

结果如下：最后一列是我需要的结果：

---

很高兴您将示例数据发布为DDL+DML，但是这些图像无助于理解这个问题，它们只会让问题变得更难，至少对我来说是这样。在当前输出旁边清晰地显示所需输出的文本将有很大帮助。抱歉@ZoharPeled，我需要idYear，每个月重复一次，但从我的编辑中可以看出，我的尝试给了我错误的idYear最后一列-希望能更好地解释它…？即从第1行到第11行，我需要idYear为1，从第12行到第23行，我需要idYear为2，等等。不幸的是，这不起作用，因为根据我的@year表，我的周期从2014年8月开始，到2015年6月结束，这是我面临的困境，这个特定时间的周期需要为1。对于第2阶段，我的开始日期是2015年7月，结束日期是2015年6月，应该是第2阶段的开始日期，以此类推。