Typescript 是否声明与给定函数的参数列表兼容的数组类型？

对于

ItemArgs

，您可以使用：

---

实际上，我第一次正确地编写了

map（）

调用，然后我又过度缩写了。感谢您的快速回答，我现在不知道为什么在文档中找不到

参数。令人惊讶的是，它实际上可以在TypeScript中实现，而不引入新的语言特性。
function item(
    tag:     string,
    kind?:   string,
    name?:   string
) : string {

   return ` * ${tag}${kind ? ` [${kind}]` : ""}${name ? ` ${name}` : ""}`;
}

/*
 * Here, I need to declare the type ItemArgs that will be an array type
 * compatible with the argument list of the item() function.
 * 
 * How do I?
 */

function block(
    tag:        string,
    kind?:      string,
    name?:      string,
    ...items:   ItemArgs[]
) : string {

    // the items.map() call must compile
    return ["/**", item(tag, kind, name), ...items.map(item), " */"].join("\n");
}

// ... and this must compile too
const jsDocBlock : string = block(

    'typedef', 'Object', 'Foo',
    ['property', 'boolean', 'should'],
    ['property', undefined, 'something']
);

function block(
    tag: string,
    kind?: string,
    name?: string,
    ...items: Parameters<typeof item>[]
): string {
    return [
        "/**",
        item(tag, kind, name),
        ...items.map(args => item(...args)),
        " */"
    ].join("\n");
}

const jsDocBlock: string = block(
    'typedef', 'Object', 'Foo',
    ['property', 'boolean', 'should'],
    ['property', undefined, 'something']
);

console.log(jsDocBlock);
 // "/**
 // * typedef [Object] Foo
 // * property [boolean] should
 // * property something
 // */"