Vb.net SSRS Visual Basic代码仅适用于Reporting services
我制作了一个解析器,它使用VisualBasic代码在文本中对数字进行舍入。但数字舍入仅在SSR中有效,下载时不起作用(参见xxx的平均值) 这是我的VB代码:Vb.net SSRS Visual Basic代码仅适用于Reporting services,vb.net,reporting-services,ssrs-2012,Vb.net,Reporting Services,Ssrs 2012,我制作了一个解析器,它使用VisualBasic代码在文本中对数字进行舍入。但数字舍入仅在SSR中有效,下载时不起作用(参见xxx的平均值) 这是我的VB代码: Public Function RoundAllNumbers(inputText As String) As String Dim result = inputText Dim patterns = {New PatternType With {.Pattern = "Current Usage (-?\d+\.\
Public Function RoundAllNumbers(inputText As String) As String
Dim result = inputText
Dim patterns = {New PatternType With {.Pattern = "Current Usage (-?\d+\.\d+) is negative", .Template = "Current Usage {0} is negative", .Precision = 2},
New PatternType With {.Pattern = "Current Usage, (-?\d+\.\d+) KWH", .Template = "Current Usage, {0} KWH", .Precision = 2},
New PatternType With {.Pattern = "Budget of (-?\d+\.\d+) KWH", .Template = "Budget of {0} KWH", .Precision = 2},
New PatternType With {.Pattern = "usage of (-?\d+\.\d+)", .Template = "usage of {0}", .Precision = 2},
New PatternType With {.Pattern = "average of (-?\d+\.\d+)", .Template = "average of {0}", .Precision = 0},
New PatternType With {.Pattern = "Current demand (-?\d+\.\d+)", .Template = "Current demand {0}", .Precision = 0},
New PatternType With {.Pattern = "demand of (-?\d+\.\d+)", .Template = "demand of {0}", .Precision = 0},
New PatternType With {.Pattern = "usage amount of (-?\d+\.\d+)", .Template = "usage amount of {0}", .Precision = 2}}
Dim formulaPattern = New PatternType With {.Pattern = "Usage \/ \(Demand \* Service hours\) \* (-?\d+\.?\d*) = (-?\d+\.?\d*) kWh \/ \((-?\d+\.?\d*) kW \* (-?\d+) Hours\)", .Template = "Usage / (Demand * Service hours) * {0} = {1} kWh / ({2} kW * {3} Hours)"}
Dim stdDeviation = New PatternType With {.Pattern = "standard deviation(\s-?\d\s\*)?\s(-?\d+\.\d+)", .Template = "standard deviation {0}{1}", .Precision = 0}
For Each pattern As PatternType In patterns
result = ProcessPattern(result, pattern)
Next
result = ProcessFormulaPattern(result, formulaPattern)
Return ProcessstdDeviationPattern(result, stdDeviation)
End Function
Private Function ProcessstdDeviationPattern(inputText As String, pattern As PatternType) As String
Dim r = New System.Text.RegularExpressions.Regex(pattern.Pattern)
Dim match = r.Match(inputText)
Dim inputToRoundedDict = New System.Collections.Generic.Dictionary(Of String, String)()
While match.Success
Dim inputSnippet = match.Groups(0).ToString()
inputSnippet = System.Text.RegularExpressions.Regex.Replace(inputSnippet, "\*", "\*")
If Not inputToRoundedDict.ContainsKey(inputSnippet) Then
Dim parsedDouble = Double.Parse(match.Groups(2).ToString())
Dim roundedDouble = Math.Round(parsedDouble, pattern.Precision)
Dim roundedSnippet = String.Format(pattern.Template, {match.Groups(1).ToString(), roundedDouble})
inputToRoundedDict.Add(inputSnippet, roundedSnippet)
End If
match = match.NextMatch()
End While
Dim result As String = inputText
For Each kvp As System.Collections.Generic.KeyValuePair(Of String, String) In inputToRoundedDict
result = System.Text.RegularExpressions.Regex.Replace(result, kvp.Key, kvp.Value)
Next
Return result
End Function
Private Function ProcessFormulaPattern(inputText As String, pattern As PatternType) As String
Dim r = New System.Text.RegularExpressions.Regex(pattern.Pattern)
Dim match = r.Match(inputText)
Dim inputToRoundedDict = New System.Collections.Generic.Dictionary(Of String, String)()
While match.Success
Dim inputSnippet = match.Groups(0).ToString()
inputSnippet = System.Text.RegularExpressions.Regex.Replace(inputSnippet, "\*", "\*")
inputSnippet = System.Text.RegularExpressions.Regex.Replace(inputSnippet, "\(", "\(")
inputSnippet = System.Text.RegularExpressions.Regex.Replace(inputSnippet, "\)", "\)")
inputSnippet = System.Text.RegularExpressions.Regex.Replace(inputSnippet, "\/", "\/")
If Not inputToRoundedDict.ContainsKey(inputSnippet) Then
Dim parsedUsage = Double.Parse(match.Groups(2).ToString())
Dim parsedDemand = Double.Parse(match.Groups(3).ToString())
Dim roundedUsage = Math.Round(parsedUsage, 2)
Dim roundedDemand = Math.Round(parsedDemand, 0)
Dim roundedSnippet = String.Format(pattern.Template, {match.Groups(1).ToString(), roundedUsage, roundedDemand, match.Groups(4).ToString()})
inputToRoundedDict.Add(inputSnippet, roundedSnippet)
End If
match = match.NextMatch()
End While
Dim result As String = inputText
For Each kvp As System.Collections.Generic.KeyValuePair(Of String, String) In inputToRoundedDict
result = System.Text.RegularExpressions.Regex.Replace(result, kvp.Key, kvp.Value)
Next
Return result
End Function
Class PatternType
Public Pattern As String
Public Template As String
Public Precision As Integer
End Class
Private Function ProcessPattern(inputText As String, pattern As PatternType) As String
Dim r = New System.Text.RegularExpressions.Regex(pattern.Pattern)
Dim match = r.Match(inputText)
Dim inputToRoundedDict = New System.Collections.Generic.Dictionary(Of String, String)()
While match.Success
Dim inputSnippet = match.Groups(0).ToString()
If Not inputToRoundedDict.ContainsKey(inputSnippet) Then
Dim parsedDouble = Double.Parse(match.Groups(1).ToString())
Dim roundedDouble = Math.Round(parsedDouble, pattern.Precision)
Dim roundedSnippet = String.Format(pattern.Template, roundedDouble)
inputToRoundedDict.Add(inputSnippet, roundedSnippet)
End If
match = match.NextMatch()
End While
Dim result As String = inputText
For Each kvp As System.Collections.Generic.KeyValuePair(Of String, String) In inputToRoundedDict
result = System.Text.RegularExpressions.Regex.Replace(result, kvp.Key, kvp.Value)
Next
Return result
End Function
可能问题是因为我在代码中使用了类。虽然我还没有在互联网上的SSRS中发现VB的任何限制
只有在SSR上查看报告时,代码才起作用的原因是什么?我以前在这份报告中有舍入代码,它起作用了。但是在我的更新之后,它只在一个地方起作用。您的VB代码很可能使用了服务器上未启用的权限。要实现这一点,您必须深入了解服务器设置,并准确确定涉及哪些权限。根据我的经验,这很难实施和维护
另一种方法是将此代码转换为数据库中的存储过程。这样,当您部署报表时,它将继续工作 原因如配置中所示。ssrs服务器url在web.config中配置,当我的代码版本部署到QAenv时,web.config中的ssrs服务器链接被设置到Stagingenv,其中报告代码未更新为什么在基础报告查询中将数字四舍五入为文本而不是四舍五入?