VHDL将8位数字转换为十六进制
我是VHDL新手,我正在努力从8个开关获取输入,以创建一个8位数字,我可以将其转换为十六进制,在两个7段显示器上显示 这是我目前的代码,他们的代码不多,因为我不知道从这里去哪里VHDL将8位数字转换为十六进制,vhdl,quartus,Vhdl,Quartus,我是VHDL新手,我正在努力从8个开关获取输入,以创建一个8位数字,我可以将其转换为十六进制,在两个7段显示器上显示 这是我目前的代码,他们的代码不多,因为我不知道从这里去哪里 ENTITY swToHex IS PORT ( SW : IN STD_LOGIC_VECTOR(7 DOWNTO 0); HEX : OUT STD_LOGIC_VECTOR(5 DOWNTO 0) ); END swToHex; ARCHITECTURE Stru
ENTITY swToHex IS
PORT (
SW : IN STD_LOGIC_VECTOR(7 DOWNTO 0);
HEX : OUT STD_LOGIC_VECTOR(5 DOWNTO 0)
);
END swToHex;
ARCHITECTURE Structural OF swToHex IS
SIGNAL A : STD_LOGIC_VECTOR(7 downto 0);
BEGIN
A(7 downto 0) <= SW(7 downto 0);
END Structural;
实体swToHex是
港口(
SW:标准逻辑向量(7到0);
十六进制:输出标准逻辑向量(5到0)
);
结束swToHex;
swToHex的体系结构是
信号A:标准逻辑向量(7到0);
开始
A(7到0)不能直接为七段显示分配十六进制数。你需要使用一个解码器。从中复制代码
此外,十六进制不是6位,通常应该是7位
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity to_7seg is
Port ( A : in STD_LOGIC_VECTOR (3 downto 0);
seg7 : out STD_LOGIC_VECTOR (6 downto 0)
);
end to_7seg;
architecture Behavioral of to_7seg is
begin
--'a' corresponds to MSB of seg7 and 'g' corresponds to LSB of seg7.
process (A)
BEGIN
case A is
when "0000"=> seg7 <="0000001"; -- '0'
when "0001"=> seg7 <="1001111"; -- '1'
when "0010"=> seg7 <="0010010"; -- '2'
when "0011"=> seg7 <="0000110"; -- '3'
when "0100"=> seg7 <="1001100"; -- '4'
when "0101"=> seg7 <="0100100"; -- '5'
when "0110"=> seg7 <="0100000"; -- '6'
when "0111"=> seg7 <="0001111"; -- '7'
when "1000"=> seg7 <="0000000"; -- '8'
when "1001"=> seg7 <="0000100"; -- '9'
when "1010"=> seg7 <="0001000"; -- 'A'
when "1011"=> seg7 <="1100000"; -- 'b'
when "1100"=> seg7 <="0110001"; -- 'C'
when "1101"=> seg7 <="1000010"; -- 'd'
when "1110"=> seg7 <="0110000"; -- 'E'
when "1111"=> seg7 <="0111000"; -- 'F'
when others => NULL;
end case;
end process;
end Behavioral;
seg1 : to_7seg port map(A(3 downto 0),HEX0);
seg2 : to_7seg port map(A(7 downto 4),HEX1);