Groovy:从文件中读取xml并向其添加节点

Groovy:从文件中读取xml并向其添加节点,xml,groovy,xml-parsing,Xml,Groovy,Xml Parsing,我在位置(C:/Users/abc.XML)有一个XML文件abc.XML,我想通过添加一个模块依赖项来更新它 abc.xml <?xml version="1.0" encoding="UTF-8"?> <!-- ~ This is free software; you can redistribute it and/or modify it ~ under the terms of the GNU Lesser General Public License as

我在位置(C:/Users/abc.XML)有一个XML文件abc.XML,我想通过添加一个模块依赖项来更新它

abc.xml

<?xml version="1.0" encoding="UTF-8"?>

<!--
  ~ This is free software; you can redistribute it and/or modify it
  ~ under the terms of the GNU Lesser General Public License as
  ~ published by the Free Software Foundation; either version 2.1 of
  ~ the License, or (at your option) any later version.
  -->

<module xmlns="urn:jboss:module:1.3" name="org.picketbox">
    <!-- This module is deprecated and subject to being removed in a subsequent release. -->
    <properties>
      <property name="jboss.api" value="deprecated"/>
    </properties>

    <resources>
        <resource-root path="picketbox-4.9.6.Final.jar"/>
        <resource-root path="picketbox-infinispan-4.9.6.Final.jar"/>
        <resource-root path="picketbox-commons-1.0.0.final.jar"/>
    </resources>

    <dependencies>
        <module name="javax.api"/>
        <module name="javax.persistence.api" optional="true"/>
    </dependencies>
</module>
这不是没有任何错误的工作,相同的代码用于简单xml(没有任何注释,只有一个节点)文件。

试试这个

import groovy.xml.QName
import groovy.xml.XmlUtil

def xml = new File("C:/Users/abc.xml").text
def parser = new XmlParser()
def root = parser.parseText(xml)
def numberOfResults = parser.createNode(root.dependencies[0], new QName("module"), ["name":"javax.xyz"])
println XmlUtil.serialize(root)
您可以参考此处的文档

import groovy.xml.QName
import groovy.xml.XmlUtil

def xml = new File("C:/Users/abc.xml").text
def parser = new XmlParser()
def root = parser.parseText(xml)
def numberOfResults = parser.createNode(root.dependencies[0], new QName("module"), ["name":"javax.xyz"])
println XmlUtil.serialize(root)