Algorithm Golang程序中的随机函数与持久性
我的计划如下: 我想做的是看看是否有一种方法可以创建一个随机函数,或者使用一个内置函数,能够使用这个程序中的哪些食物是从随机选择中选择的,并且在接下来的一周内不再使用?我目前的食物设置为1-6,但我想确保一周内不会连续两次选择相同的食物(例如2)。此外,我希望该计划能够有可能写什么,最后一个项目是选定的,所以它不会再选择它至少一个星期。我能用一个简单的文本文件来完成这个任务吗Algorithm Golang程序中的随机函数与持久性,algorithm,go,persistence,Algorithm,Go,Persistence,我的计划如下: 我想做的是看看是否有一种方法可以创建一个随机函数,或者使用一个内置函数,能够使用这个程序中的哪些食物是从随机选择中选择的,并且在接下来的一周内不再使用?我目前的食物设置为1-6,但我想确保一周内不会连续两次选择相同的食物(例如2)。此外,我希望该计划能够有可能写什么,最后一个项目是选定的,所以它不会再选择它至少一个星期。我能用一个简单的文本文件来完成这个任务吗 package main import ( "fmt" "math/rand" "time"
package main
import (
"fmt"
"math/rand"
"time"
)
type Recipe struct { //Struct for recipe information
name string
prepTime int
cookTime int
Ingredients []string //this is now a slice that will accept multiple elements
ID int
Yield int
}
func main() {
var recipe1 Recipe //Declare recipe1 of Type Recipe
var recipe2 Recipe
var recipe3 Recipe
/* recipe1 specifications */
recipe1.name = "BBQ Pulled Chicken"
recipe1.prepTime = 25
recipe1.cookTime = 5
recipe1.Ingredients = append(
recipe1.Ingredients,
"1 8-ounce can reduced-sodium tomato sauce",
)
recipe1.Ingredients = append(
recipe1.Ingredients,
"1/2 medium onion (grated),",
)
recipe1.ID = 1
recipe1.Yield = 8
/* Recipe 2 specifications */
recipe2.name = "Steak Tacos with Pineapple"
recipe2.prepTime = 45
recipe2.cookTime = 45
recipe2.Ingredients = append(
recipe2.Ingredients,
"3 tablespoons soy sauce,",
)
recipe2.Ingredients = append(
recipe2.Ingredients,
"1 tablespoon finely grated garlic,",
)
recipe2.Ingredients = append(
recipe2.Ingredients,
"1 tablespoon finely grated peeled fresh ginger,",
)
recipe2.Ingredients = append(
recipe2.Ingredients,
"1 1/2 pounds skirt steak, cut into 5-inch lengths,",
)
recipe2.Ingredients = append(
recipe2.Ingredients,
"Salt",
)
recipe2.Ingredients = append(
recipe2.Ingredients,
"Pepper",
)
recipe2.ID = 2
recipe2.Yield = 4
recipe3.name = "Simple Lemon Herb Chicken"
recipe3.prepTime = 10
recipe3.cookTime = 15
recipe3.Ingredients = append(
recipe3.Ingredients,
"2 skinless boneless chicken breast halves,",
)
recipe3.Ingredients = append(
recipe3.Ingredients,
"1 Lemon,",
)
recipe3.Ingredients = append(
recipe3.Ingredients,
"Salt and Pepper to taste,",
)
recipe3.Ingredients = append(
recipe3.Ingredients,
"1 tablespoon olive oil,",
)
recipe3.Ingredients = append(
recipe3.Ingredients,
"2 sprigs fresh parsley (for garnish),",
)
recipe3.Ingredients = append(
recipe3.Ingredients,
"1 pinch dried oregano,",
)
recipe3.ID = 3
recipe3.Yield = 2
//call to printRecipe function below
printRecipe(recipe1)
totalTime(recipe1)
printRecipe(recipe2)
totalTime(recipe2)
printRecipe(recipe3)
totalTime(recipe3)
//choose random number for recipe
rand.Seed(time.Now().UTC().UnixNano())
myrand := random(1, 6)
fmt.Println(myrand)
//logic for recipe to choose
if myrand == 1 {
fmt.Println(1)
printRecipeOfTheDay(recipe1)
} else if myrand == 2 {
fmt.Println(2)
printRecipeOfTheDay(recipe2)
} else if myrand == 3 {
fmt.Println(3)
printRecipeOfTheDay(recipe3)
} else if myrand == 4 {
fmt.Println(4)
}
}
//function to print Recipe
func printRecipe(recipe Recipe) {
fmt.Printf("Recipe Name : %s\n", recipe.name)
fmt.Printf("Prep Time : %d\n", recipe.prepTime)
fmt.Printf("Cook Time : %d\n", recipe.cookTime)
fmt.Printf("Ingredients : %s\n", recipe.Ingredients)
fmt.Printf("Recipe ID : %d\n", recipe.ID)
}
//random number function
func random(min, max int) int {
return rand.Intn(max-min) + min
}
//function to print the winner for recipe of the day to use
//for either lunch or dinner
func printRecipeOfTheDay(recipe Recipe) {
fmt.Printf("The recipe of the day is : %s\n", recipe.name)
}
//Returns total time by addings cookTime and prepTime
func totalTime(recipe Recipe) {
fmt.Printf("The total time for this recipe is %d\n", recipe.cookTime+recipe.prepTime)
}
正如@Volker所说,烫发很可能是您想要使用的。下面的示例将为您生成伪随机列表。您可以将其保存到json编码的文件中。然后,如果你有7个食谱,你可以利用time.Weekday从切片中获取一个食谱编号,使用星期几作为切片的键。一旦你到达某个预先确定的日期,只需重新生成切片并保存即可
package main
import "fmt"
import "math/rand"
import "time"
func main() {
r := rand.New(rand.NewSource(time.Now().UnixNano()))
i := r.Perm(6)
fmt.Printf("%v\n", i)
}
你正在寻找一个排列:数学/随机排列中的排列你知道我可能遵循的一个例子吗?有趣的是,我注意到输出为[5 2 3 0 1 4]我如何能够将其中一个数字读入一个变量中单独处理?例如,我想把5读入一个我称之为monday的变量,它是一个int片,所以你可以引用片中包含的任何int,比如i[0]或i[5],直到i[len(i)-1]。在这之后,你会得到一个越界的错误。哇,这是完美的,谢谢肖恩!正是我要找的!