Android 向已存在重复编号的列表中添加编号
这一个非常适合阵列。我需要一些帮助与重复在现有的数字只列出Android 向已存在重复编号的列表中添加编号,android,Android,这一个非常适合阵列。我需要一些帮助与重复在现有的数字只列出 /* ADDING NUMBERS TO ArrayLIST AND IF NEW NUMBER ENTERED SAME AS already EXISTING NUMBER RESAULT IS DUBLICATE; */ private String[] phoneNumbers; public String addPhoneNumber(String newPhoneNumber) throws SMSDataModelFu
/*
ADDING NUMBERS TO ArrayLIST AND IF NEW NUMBER ENTERED SAME AS already EXISTING NUMBER
RESAULT IS DUBLICATE;
*/
private String[] phoneNumbers;
public String addPhoneNumber(String newPhoneNumber) throws SMSDataModelFullException {
String result;
if (numPhoneNumbers == phoneNumbers.length) {
result = FULL;
} else {
boolean exists;
exists = findPhoneNumberIndex(newPhoneNumber) != -1;
if (exists) {
result = DUPLICATE;
} else {
phoneNumbers[numPhoneNumbers] = newPhoneNumber;
numPhoneNumbers++;
result = newPhoneNumber;
}
}
return result;
}
私人列表电话号码;
公共字符串addPhoneNumber(字符串newPhoneNumber)引发SMSDataModelFullException{
字符串结果;
if(maxNumPhoneNumbers!=0&&phoneNumber.size()>=maxNumPhoneNumbers){
抛出新的SMSDataModelFullException(newPhoneNumber);
}
否则{
布尔存在;
exist=findPhoneNumberIndex(新电话号码)!=-1;
如果(存在)
{
结果=重复;
}
否则{
添加(新电话号码);
}
返回newPhoneNumber;
}
}
这个坏了,我做错了什么?重复输入列表未显示原因。您始终返回
newPhoneNumber
private List<String> phoneNumber;
public String addPhoneNumber(String newPhoneNumber) throws SMSDataModelFullException {
String result;
if (maxNumPhoneNumbers!=0 && phoneNumber.size() >= maxNumPhoneNumbers) {
throw new SMSDataModelFullException(newPhoneNumber);
}
else{
boolean exist;
exist =findPhoneNumberIndex(newPhoneNumber)!= -1;
if(exist)
{
result = DUPLICATE;
}
else{
phoneNumber.add(newPhoneNumber);
}
return newPhoneNumber;
}
}
public String addPhoneNumber(String newPhoneNumber) {
String result = newPhoneNumber;
if(!phoneNumber.contains(newPhoneNumber)){ // if it is not already in the list
phoneNumber.add(newPhoneNumber); // add it to the list
}else{
result = "DUPLICATE"; // if number was already in the list result = DUPLICATE
}
return result;
}
执行与第一种情况相同的操作
return newPhoneNumber;
您的
findPhoneNumberIndex()
也可以替换为phoneNumber.contains(newPhoneNumber)
您的问题不清楚。你能再澄清一点吗?发布findPhoneNumberIndex()
如何更改if(numPhoneNumbers==phoneNumbers.length)以列出?也许可以使用size或contain代替.length?很高兴能提供帮助。请您投票接受我的答案,因为它对您有帮助吗?:)在我的答案后面和答案的分数下面一定有一个灰色的勾号。您单击它,它将变为绿色!:)
...
if (exists) {
result = DUPLICATE;
} else {
phoneNumber.add(newPhoneNumber);
result = newPhoneNumber;
}
}
return result;