Android 未正确获取Google places结果
我正试图在json中获得Google places的结果。但每次我都得到了结果 请求状态被拒绝Android 未正确获取Google places结果,android,json,url,google-places,Android,Json,Url,Google Places,我正试图在json中获得Google places的结果。但每次我都得到了结果 请求状态被拒绝 package com.json.trial; public class GetMethodEx { String API_KEY = "My Places Key"; String baseUrl="https://maps.googleapis.com/maps/api/place/search/json?"; key="AIzaSyCQ6m78y0CLClp
package com.json.trial;
public class GetMethodEx {
String API_KEY = "My Places Key";
String baseUrl="https://maps.googleapis.com/maps/api/place/search/json?";
key="AIzaSyCQ6m78y0CLClpvldSwY-aI2JbbZGoFx68";
double latitude,longitude;
public String getInternetData()throws Exception{
latitude=-33.8670522;
longitude=151.1957362;
GenericUrl reqUrl = new GenericUrl(baseUrl);
reqUrl.put("location", Double.toString(latitude) + "," + Double.toString(longitude));
reqUrl.put("radius", 500);
reqUrl.put("types", "");
reqUrl.put("sensor", "false");
reqUrl.put("key", API_KEY);
BufferedReader in = null;
String data = null;
try{
HttpClient client = new DefaultHttpClient();
URI website = new URI (baseUrl);
HttpGet request = new HttpGet();
request.setURI(website);
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String l="";
String nl = System.getProperty("line.separator");
while((l=in.readLine())!= null){
sb.append(l + nl);
}
in.close();
data = sb.toString();
return data;
}finally{
if(in!=null){
try{
in.close();
return data;
}catch(Exception e){
e.printStackTrace();
}
}
}
}
}
您没有在中传递
reqUrl
URI website = new URI (baseUrl);
试试这个:
URI website = new URI (reqUrl);
我试过学校和食物类型我试过这个,如果你直接在一行中输入特定纬度和经度的url,它就工作了…但是当我以上面的方式提供url时..它只是空结果和请求状态被拒绝看到上面的代码..你能告诉我我提供的方式吗从CurrentLocation类到main类的纬度和经度是否良好..顺便说一句,谢谢你的回复…同时我会尝试一下并让你知道..谢谢你的回复..我已经完成了你告诉的…但仍然没有帮助。但我发现了我的问题并解决了。请分享,你的解决方案是什么?