Coq “未知”的解释_/_&引用；尽管进口了Arith
我试图编写一个函数，将Coq “未知”的解释_/_&引用；尽管进口了Arith,coq,Coq,我试图编写一个函数，将nat转换为coq中的string。这是我的尝试 Require Import Arith String. (* append is part of the string library. Its signature is (s1 : string) : string -> string *) Fixpoint convert_nat_to_string (n : nat) : string := match n with
natcoqstringRequire Import Arith String.
(*
append is part of the string library. Its signature is
(s1 : string) : string -> string
*)
Fixpoint convert_nat_to_string (n : nat) : string :=
match n with
| 0 => String "0" EmptyString
| 1 => String "1" EmptyString
| 2 => String "2" EmptyString
| 3 => String "3" EmptyString
| 4 => String "4" EmptyString
| 5 => String "5" EmptyString
| 6 => String "6" EmptyString
| 7 => String "7" EmptyString
| 8 => String "8" EmptyString
| 9 => String "9" EmptyString
| _ => (append (convert_nat_to_string (n/10))) (convert_nat_to_string (n mod 10))
end.
coqideArith证明
/ArithCoq < Require Import Arith.
[Loading ML file z_syntax_plugin.cmxs ... done]
[Loading ML file quote_plugin.cmxs ... done]
[Loading ML file newring_plugin.cmxs ... done]
<W> Grammar extension: in [tactic:simple_tactic], some rule has been masked
<W> Grammar extension: in [tactic:simple_tactic], some rule has been masked
<W> Grammar extension: in [tactic:simple_tactic], some rule has been masked
<W> Grammar extension: in [tactic:simple_tactic], some rule has been masked
<W> Grammar extension: in [tactic:simple_tactic], some rule has been masked
Coq < Check 5/10.
5 / 10
: nat
Coq<需要导入算术。
[正在加载ML文件z_syntax_plugin.cmxs…完成]
[正在加载ML文件quote_plugin.cmxs…完成]
[正在加载ML文件newring_plugin.cmxs…完成]
语法扩展：在[策略：简单策略]中，一些规则被掩盖了
语法扩展：在[策略：简单策略]中，一些规则被掩盖了
语法扩展：在[策略：简单策略]中，一些规则被掩盖了
语法扩展：在[策略：简单策略]中，一些规则被掩盖了
语法扩展：在[策略：简单策略]中，一些规则被掩盖了
Coq<检查5/10。
5/10
：纳特
Coq.Arith.PeanoNatRequire Import Coq.Arith.PeanoNat.
Check 10 / 5. (* --> 10 / 5 : nat *)
我用的是coq8.6。我按原样尝试了您的代码，但无法重现您看到的错误。您将看到另一个与总体性有关的错误。您可以使用
程序定点字符串_natcoqidecoqcoqtop-v8.5pl138.4pl5