C++ C++；/OpenGL-数组的指针

我目前在将鼠标坐标存储到数组中时遇到了一个问题，在该数组中，该数组的指针被传递给一个函数，然后该函数将使用这些坐标在屏幕上显示一条多段线

下面是我的代码。请注意，我已经对问题所在进行了评论，但我认为我还是要粘贴大部分代码：

struct mousePoint{
    int x, y;
};

struct Node{
    mousePoint *pointer;
    int corner;
    Node *next;
};

Node *Top;
Node *Bottom;


void init(void){ // doesnt need to be shown, but initialises linked list

// Adds the mouse coords array to the top of the linked list
void AddLines(mousePoint Lines[], int corner){
    Node *temp;
    temp = new Node;
    cout << "(AddLines func) array x1: ";
cout << Lines[0].x << endl;
cout << "(AddLines func) array y1: ";
cout << Lines[0].y << endl;
cout << "(AddLines func) array x2: ";
cout << Lines[1].x << endl;
cout << "(AddLines func) array y1: ";
cout << Lines[1].y << endl;
    temp->pointer = Lines; // <--- I believe this is the error
    temp->corner = corner;
    temp->next = NULL;
    if(Top == NULL){
        Top = temp;
    }else{
        temp->next = Top;
        Top = temp;
        if(Bottom == NULL){
            Bottom = Top;
        }
    }
}

// Draws the polyline based on the coords in the array
void DrawLines(mousePoint Lines[], int corner){
    cout << "(DrawLines func) array x1: ";
cout << Lines[0].x << endl;
cout << "(DrawLines func) array y1: ";
cout << Lines[0].y << endl;
cout << "(DrawLines func) array x2: ";
cout << Lines[1].x << endl;
cout << "(DrawLines func) array y1: ";
cout << Lines[1].y << endl;
    glBegin(GL_LINE_STRIP);
        for(int i = 0; i < corner; i++){
            glVertex2i(Lines[i].x, Lines[i].y);
        }
    glEnd();

}

void display(void){
    Node *current;
        current = Top;
                // cycle through all polylines in linked list
        for(; current != NULL; current = current->next){ 
            DrawLines(current->pointer, current->corner);
        }
    glFlush();
}

void mouse(int button, int state, int x, int y)
{
    static mousePoint Lines[100]; // array to store mouse coords
    static int NumCorner = 0; // counter for mouse click
    if(button == GLUT_LEFT_BUTTON && state == GLUT_DOWN)
    {
        Lines[NumCorner].x = x;
        Lines[NumCorner].y = 480 - y;
                // draw individual points
        glBegin(GL_POINTS);
        glVertex2i(Lines[NumCorner].x, Lines[NumCorner].y); 
        glEnd();
        NumCorner++;
    }else if(button == GLUT_RIGHT_BUTTON && state == GLUT_DOWN){
        AddLines(Lines, NumCorner); // add mouse coords to linked list
        NumCorner = 0; // reset counter back to 0
    }
}

int main(int argc, char** argv) // doesnt need to be shown

注意它如何在不将其添加到指针的情况下绘制一条额外的线

我曾经尝试过使用memcpy——如果使用的点数少于5-6点，那么这些线就画得非常完美，再多的话，应用程序就会崩溃。因此，我相信这是指针问题，好吧，我想我明白了

您正在使用静态数组行[]。当您执行“temp->pointer=Lines”时，您将为每个多边形指向此静态数组。因此，当绘制第一个多边形，然后尝试开始第二个多边形时，您正在编辑第一个多边形的线

您可以复制for循环中的每个点，迭代“角点”次，而不是您已经发现有问题的线

相反：

temp->pointer = Lines; // <--- I believe this is the error

temp->pointer=行；//指针=新鼠标点[角点]；
对于（int a=0；a指针[a]=行[a]；
}

您不使用std:：list或std:：vector和std:：vector有什么原因吗？仅供参考，这确实让事情更容易看。没有特别的原因，现在就这样做吧

temp->pointer = Lines; // <--- I believe this is the error

temp->pointer = new mousePoint[corner];
for(int a = 0; a < corner; a++)
{
   temp->pointer[a] = Lines[a];
}