如何将结构的C++／CLI数组编排到非托管C++ 我正在寻找正确的语法，将结构数组传递给非托管C++ DLL。< /P>

我的dll导入如下所示

    #define _DllImport [DllImport("Controller.dll", CallingConvention = CallingConvention::Cdecl)] static
_DllImport bool _Validation(/* array of struct somehow */);

在我的客户端代码中

List<MyStruct^> list;
MyObject::_Validation(/* list*/);

我知道System:：Runtime:：InteropServices:：Marshal有很多有用的方法来做类似的事情，但我不确定该使用哪种方法。

您可以使用它来获取一个IntPtr，该IntPtr可以传递到本机MyStruct*数组中

但是，我不知道如何直接从列表中执行此操作。我认为您需要将其转换为一个数组，并使用pin_ptr来防止GC在将内存传递到本机代码之前移动内存。

您可以使用它来获取一个IntPtr，该IntPtr可以传递到本机MyStruct*数组中

---

但是，我不知道如何直接从列表中执行此操作。我认为您需要将其转换为一个数组，并使用一个pin_ptr来防止GC在将内存传递给本机代码之前移动内存。

使用StructLayout创建非托管结构的托管版本。请确保按相同的顺序排列。然后，您应该能够像将其传递给任何托管函数一样传递它，例如ValidationMyStruct[]pStructs

例如，假设我们的本机函数具有以下原型：

extern "C" {

STRUCTINTEROPTEST_API int fnStructInteropTest(MYSTRUCT *pStructs, int nItems);

}

本机MYSTRUCT的定义如下：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

然后在C中，定义结构的托管版本，如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

管理的原型如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

然后，您可以调用传递MYSTRUCT结构数组的函数，如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

---

使用StructLayout创建非托管结构的托管版本。请确保按相同顺序放置。然后，您应该能够像将其传递给任何托管函数一样传递它，例如ValidationMyStruct[]pStructs

例如，假设我们的本机函数具有以下原型：

extern "C" {

STRUCTINTEROPTEST_API int fnStructInteropTest(MYSTRUCT *pStructs, int nItems);

}

本机MYSTRUCT的定义如下：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

然后在C中，定义结构的托管版本，如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

管理的原型如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }

然后，您可以调用传递MYSTRUCT结构数组的函数，如下所示：

struct MYSTRUCT
{
    int a;
    int b;
    char c;
};

[System.Runtime.InteropServices.StructLayoutAttribute(System.Runtime.InteropServices.LayoutKind.Sequential)]
public struct MYSTRUCT
{
    public int a;
    public int b;
    public byte c;
}

    [System.Runtime.InteropServices.DllImportAttribute("StructInteropTest.dll", EntryPoint = "fnStructInteropTest")]
    public static extern int fnStructInteropTest(MYSTRUCT[] pStructs, int nItems);

    static void Main(string[] args)
    {
        MYSTRUCT[] structs = new MYSTRUCT[5];

        for (int i = 0; i < structs.Length; i++)
        {
            structs[i].a = i;
            structs[i].b = i + structs.Length;
            structs[i].c = (byte)(60 + i);
        }

        NativeMethods.fnStructInteropTest(structs, structs.Length);

        Console.ReadLine();
    }