C++ 使用GLM在OpenGL中绘制2个立方体

因此，我可以使用OpenGL3.2+绘制旋转立方体，并将其从0,0,0平移到左侧，但当我尝试绘制第二个立方体（向右）时，它不会渲染

这是我的显示功能：

    void display()                                  
    {
    glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
    glUseProgram(myShader.handle());

    GLuint matLocation = glGetUniformLocation(myShader.handle(), "ProjectionMatrix");
    glUniformMatrix4fv(matLocation, 1, GL_FALSE, &ProjectionMatrix[0][0]);

    spinY+=0.03;
    if(spinY>360) spinY = 0;

    glm::mat4 viewMatrix;
    viewMatrix = glm::translate(glm::mat4(1.0),glm::vec3(0,0,-100));        //viewing matrix
    ModelViewMatrix = glm::translate(viewMatrix,glm::vec3(-30,0,0));        //translate object from the origin
    ModelViewMatrix = glm::rotate(ModelViewMatrix,spinY, glm::vec3(0,1,0));                 //rotate object about y axis

    glUniformMatrix4fv(glGetUniformLocation(myShader.handle(), "ModelViewMatrix"), 1, GL_FALSE, &ModelViewMatrix[0][0]); //pass matrix to shader

    //Add the following line just before the line to draw the cube to 
    //check that the origin of the cube in eye space is (-30, 0, -100);
    result = glm::vec3(ModelViewMatrix * glm::vec4(0,0,0,1));
    std::cout<<glm::to_string(result)<<std::endl; //print matrix to get coordinates.

    myCube.render();
    glUseProgram(0);
    }

更新

着色器：

    uniform mat4 ModelViewMatrix;
    //uniform mat4 ModelViewMatrix_Two; //NOT NEEDED - USED SAME SHADER OBJECT
    uniform mat4 ProjectionMatrix;

    in  vec3 in_Position;  // Position coming in
    in  vec3 in_Color;     // colour coming in
    out vec3 ex_Color;     // colour leaving the vertex, this will be sent to the fragment shader

    void main(void)
    {
    gl_Position = ProjectionMatrix * ModelViewMatrix * vec4(in_Position, 1.0);
    //gl_Position = ProjectionMatrix * ModelViewMatrix_Two * vec4(in_Position, 1.0);
    ex_Color = in_Color;
    }

---

除非着色器具有名为ModelViewMatrix_-Two的统一属性，否则这将无法工作。我看不出为什么着色器需要另一个统一的模型视图，因为您没有在同一调用中绘制两个立方体。如果不是问题，你能发布你的着色器代码吗？

最后，我创建了第二个立方体对象，第二个查看矩阵，并将它们与着色器中已经建立的模型矩阵一起使用，似乎两个立方体都被单独调用/渲染

正确的代码是：

    glm::mat4 viewMatrix_Two, ModelViewMatrix_Two;
    viewMatrix_Two = glm::translate(glm::mat4(1.0),glm::vec3(0,0,-200));
    ModelViewMatrix = glm::translate(viewMatrix_Two,glm::vec3(30,0,0));
    ModelViewMatrix = glm::rotate(ModelViewMatrix,spinX, glm::vec3(1,0,0));

    glUniformMatrix4fv(glGetUniformLocation(myShader.handle(), "ModelViewMatrix"), 1, GL_FALSE, &ModelViewMatrix[0][0]); //pass matrix to shader

    myCube_Two.render();

---

哦，我想念你。。。你说得对，我的着色器中没有提供ModelViewMatrix\u 2。。。我会试试。修正了均匀性后，它现在只渲染首先传递给着色器的ModelViewMatrix…解决了。谢谢你的帮助。。。我只需要视图的第二个矩阵，并将其与着色器中的现有模型矩阵一起使用。。。现在一切正常。我将在下面发布正确的代码。谢谢

    uniform mat4 ModelViewMatrix;
    //uniform mat4 ModelViewMatrix_Two; //NOT NEEDED - USED SAME SHADER OBJECT
    uniform mat4 ProjectionMatrix;

    in  vec3 in_Position;  // Position coming in
    in  vec3 in_Color;     // colour coming in
    out vec3 ex_Color;     // colour leaving the vertex, this will be sent to the fragment shader

    void main(void)
    {
    gl_Position = ProjectionMatrix * ModelViewMatrix * vec4(in_Position, 1.0);
    //gl_Position = ProjectionMatrix * ModelViewMatrix_Two * vec4(in_Position, 1.0);
    ex_Color = in_Color;
    }

    glm::mat4 viewMatrix_Two, ModelViewMatrix_Two;
    viewMatrix_Two = glm::translate(glm::mat4(1.0),glm::vec3(0,0,-200));
    ModelViewMatrix = glm::translate(viewMatrix_Two,glm::vec3(30,0,0));
    ModelViewMatrix = glm::rotate(ModelViewMatrix,spinX, glm::vec3(1,0,0));

    glUniformMatrix4fv(glGetUniformLocation(myShader.handle(), "ModelViewMatrix"), 1, GL_FALSE, &ModelViewMatrix[0][0]); //pass matrix to shader

    myCube_Two.render();