C# 测试用例在算法回文中失败
下午好,我正在第页上进行一个练习,我有两个测试失败案例: 小写单字:错误答案 任何情况下,一个词:错误答案 我不明白,他们是指我,因为在算法中,我控制大小写 我的算法如下:C# 测试用例在算法回文中失败,c#,algorithm,testing,C#,Algorithm,Testing,下午好,我正在第页上进行一个练习,我有两个测试失败案例: 小写单字:错误答案 任何情况下,一个词:错误答案 我不明白,他们是指我,因为在算法中,我控制大小写 我的算法如下: using System; public class Palindrome { public static char[] abecedario = new char[]{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r',
using System;
public class Palindrome
{
public static char[] abecedario = new char[]{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','w','x','y','z'};
public static char[] ABECEDARIO = new char[]{ 'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','W','X','Y','Z'};
public static bool IsPalindrome(string str)
{
string strOriginal = string.Empty;
string strInversa = string.Empty;
for(int i = str.Length-1; i >= 0; i--)
{
string concatenarInversa = string.Empty;
string concatenarOriginal = string.Empty;
for(int j = 0; j < abecedario.Length; j++)
{
if(str[i] == abecedario[j] || str[i] == ABECEDARIO[j])
{
concatenarInversa = abecedario[j].ToString();
}
if(str[(str.Length-1)-i] == abecedario[j] || str[(str.Length-1)-i] == ABECEDARIO[j] )
{
concatenarOriginal = abecedario[j].ToString();
}
if(concatenarInversa!=string.Empty && concatenarOriginal != string.Empty)
{
break;
}
}
if(concatenarInversa!=string.Empty)
{
strInversa = strInversa + concatenarInversa;
}
if(concatenarOriginal != string.Empty)
{
strOriginal = strOriginal + concatenarOriginal;
}
}
Console.WriteLine("strInversa : " + strInversa);
Console.WriteLine("strOriginal : " + strOriginal);
return strInversa == strOriginal;
}
public static void Main(string[] args)
{
Console.WriteLine(IsPalindrome("sEeS"));
}
}
使用系统;
公共类回文
{
公共静态字符[]abecardio=新字符[]{'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','w','x','y','z'};
公共静态字符[]abecardio=新字符[]{'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','W','X','Y','Z'};
公共静态bool IsPalindrome(字符串str)
{
string strOriginal=string.Empty;
string strInversa=string.Empty;
对于(int i=str.Length-1;i>=0;i--)
{
string concatenarivenversa=string.Empty;
string concatenarOriginal=string.Empty;
对于(int j=0;j
您的abecardio
变量缺少字母V(V)。试试这个:
public static char[] abecedario = new char[]{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
public static char[] ABECEDARIO = new char[]{ 'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
或者(更容易键入):
对于当前代码失败的测试示例,请考虑“VEE”一词。它不是回文,但因为您的代码忽略了字母V,所以它认为它是回文。
您是否在调试器中仔细检查了它,以查看算法哪里出了问题?如果我不明白问题是什么,请告诉我测试用例。public static char[] abecedario = "abcdefghijklmnopqrstuvwxyz".ToCharArray();
public static char[] ABECEDARIO = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();