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C# 获取查询结果汇总行总数的最佳方式

c# sql asp.net-mvc tsql

C# 获取查询结果汇总行总数的最佳方式,c#,sql,asp.net-mvc,tsql,C#,Sql,Asp.net Mvc,Tsql,我正在执行一个查询，结果得到几千行，客户需要一行显示某些数值列的总和。我通过使用分组集实现了这一点，但该函数最多支持32个不在聚合函数中的列。我的问题是，我必须返回将近45列，由于聚合函数的缘故，我在分组中只保留了10列 最初的查询是这样的： select o.Name, ci.Id, ci.OriginId, ci.Varchar1, ci.Varchar2, ci.Varchar3, ci.Varchar4, ci.V

我正在执行一个查询，结果得到几千行，客户需要一行显示某些数值列的总和。我通过使用分组集实现了这一点，但该函数最多支持32个不在聚合函数中的列。我的问题是，我必须返回将近45列，由于聚合函数的缘故，我在分组中只保留了10列

最初的查询是这样的：

    select
    o.Name, 
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20,       
    sum(ci.Decimal1) as Decimal1,
    sum(ci.Decimal1) as Decimal2,
    sum(ci.Decimal1) as Decimal3,
    sum(ci.Decimal1) as Decimal4,
    sum(ci.Decimal1) as Decimal5,
    sum(ci.Decimal1) as Decimal6,
    sum(ci.Decimal1) as Decimal7,
    sum(ci.Decimal1) as Decimal8,
    sum(ci.Decimal1) as Decimal9,
    sum(ci.Decimal1) as Decimal10,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 

group by grouping sets((
    o.Name,
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10), ())

    select      
    o.name
    ci.Id,
    ci.OriginId,
    sum(ci.Decimal1) as Decimal1,
    sum(ci.Decimal1) as Decimal2,
    sum(ci.Decimal1) as Decimal3,
    sum(ci.Decimal1) as Decimal4,
    sum(ci.Decimal1) as Decimal5,
    sum(ci.Decimal1) as Decimal6,
    sum(ci.Decimal1) as Decimal7,
    sum(ci.Decimal1) as Decimal8,
    sum(ci.Decimal1) as Decimal9,
    sum(ci.Decimal1) as Decimal10,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 


group by grouping sets((
    o.Name,
    ci.Id,
    ci.OriginId,        
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10), ())

union

select  
    o.Name,
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 

group by grouping sets((
    o.name,
    ci.Id,
    ci.OriginId,

    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20), ())
我已尝试将查询一分为二，以便GROUPBY中的列数不会达到可用的最大值。如果我分开执行每个查询，我会得到所需的结果，但是如果我合并它们，我会有一个错误（无法将nvarchar转换为数值）

结果是这样的：

    select
    o.Name, 
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20,       
    sum(ci.Decimal1) as Decimal1,
    sum(ci.Decimal1) as Decimal2,
    sum(ci.Decimal1) as Decimal3,
    sum(ci.Decimal1) as Decimal4,
    sum(ci.Decimal1) as Decimal5,
    sum(ci.Decimal1) as Decimal6,
    sum(ci.Decimal1) as Decimal7,
    sum(ci.Decimal1) as Decimal8,
    sum(ci.Decimal1) as Decimal9,
    sum(ci.Decimal1) as Decimal10,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 

group by grouping sets((
    o.Name,
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10), ())

    select      
    o.name
    ci.Id,
    ci.OriginId,
    sum(ci.Decimal1) as Decimal1,
    sum(ci.Decimal1) as Decimal2,
    sum(ci.Decimal1) as Decimal3,
    sum(ci.Decimal1) as Decimal4,
    sum(ci.Decimal1) as Decimal5,
    sum(ci.Decimal1) as Decimal6,
    sum(ci.Decimal1) as Decimal7,
    sum(ci.Decimal1) as Decimal8,
    sum(ci.Decimal1) as Decimal9,
    sum(ci.Decimal1) as Decimal10,
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 


group by grouping sets((
    o.Name,
    ci.Id,
    ci.OriginId,        
    ci.Date1,
    ci.Date2,
    ci.Date3,
    ci.Date4,
    ci.Date5,
    ci.Date6,
    ci.Date7,
    ci.Date8,
    ci.Date9,
    ci.Date10), ())

union

select  
    o.Name,
    ci.Id,
    ci.OriginId,
    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20

from 
    Items ci
    inner join Origins o 
    on ci.OriginId = o.Id 

group by grouping sets((
    o.name,
    ci.Id,
    ci.OriginId,

    ci.Varchar1,
    ci.Varchar2,
    ci.Varchar3,
    ci.Varchar4,
    ci.Varchar5,
    ci.Varchar6,
    ci.Varchar7,
    ci.Varchar8,
    ci.Varchar9,
    ci.Varchar10,
    ci.Varchar11,
    ci.Varchar12,
    ci.Varchar13,
    ci.Varchar14,
    ci.Varchar15,
    ci.Varchar16,
    ci.Varchar17,
    ci.Varchar18,
    ci.Varchar19,
    ci.Varchar20), ())
另一种方法（如果可能的话）是通过在SQL中对集合进行分组来删除该组，并用C#生成一行，因为查询的结果由IEnumerable接收，但我不知道SUM函数是否可用

如有任何建议，将不胜感激

提前感谢。

如果只有几千行，我将使用存储过程获得结果，而不将总计放入临时表或表值变量，然后将结果作为该表的<代码>联合所有< /代码>加上上面的一个大的总数。

如果你要做的是基本上所有的数据加上总的行，考虑下面的方法。不要按包含所有非聚合列的分组集分组，而是按行ID分组（现有的一个，在所有数据行中应该是唯一的，或者是人工的，使用
row\u number（）
函数创建）。还考虑在计算总数之后加入辅助表。

下面是一个例子

设置示例数据：

declare @origs table (id int, name varchar(20));
insert into @origs values (1, 'orig1'), (2, 'orig2');

declare @items table (
    id int, orig_id int,
    column1 varchar(20), column2 varchar(20),
    value1 float, value2 float);

insert into @items values
(1, 1, 'c1.1', 'c2.1', 100, 10)
,(2, 1, 'c1.2', 'c2.2', 200, 20)
,(3, 2, 'c1.3', 'c2.3', 300, 30);
下面的查询以您尝试的方式返回所有数据加上总计行：

select i.id, o.name as orig, i.column1, i.column2, sum(i.value1) val1, sum(i.value2) val2
from @items i
    join @origs o on o.id = i.orig_id
group by grouping sets ((i.id, o.name, i.column1, i.column2), ());
输出为：

id    orig  column1  column2  val1  val2
----- ----- -------- -------- ----- -----
1     orig1 c1.1     c2.1     100   10
2     orig1 c1.2     c2.2     200   20
3     orig2 c1.3     c2.3     300   30
NULL  NULL  NULL     NULL     600   60
将其与下一个查询进行比较，该查询按单个列对数据进行分组。此外，在数据分组后，辅助表
@origs
也被合并

;with items as (
    select
        case grouping(id) when 0 then max(id) else NULL end id,
        case grouping(id) when 0 then max(orig_id) else NULL end orig_id,
        case grouping(id) when 0 then max(column1) else NULL end column1,
        case grouping(id) when 0 then max(column2) else NULL end column2,
        val1 = sum(value1),
        val2 = sum(value2)
    from @items
    group by rollup (id)
)
select i.id, o.name as orig, i.column1, i.column2, i.val1, i.val2
from items i
    left join @origs o on o.id = i.orig_id;
输出相同：

你在显示数千行，每行有45列吗？是的，这是主要问题。我必须显示每一列。您是否使用循环来显示此数据？如果是这样，请计算该循环内的必要和，并在末尾显示它们。另一方面，试图在web浏览器中显示太多数据通常会以眼泪告终，以防万一，这正是您所要尝试的。我将在MVC视图中显示它，并使用一个使用IEnumerable的grid.MVC表。由于表支持分页，因此显示不是问题。我们已经对它进行了测试，显示没有摘要行的数据没有问题。你认为我应该如何计算应用程序中的金额？我想我可以考虑在一个新的表中提前计算你的“总数”行，并检索两个结果集，一个是实际数据，一个是总计，存储在新的单独表中。