django在聚合后获取基础queryset项

对于这些型号：

class Product(models.Model):
    code = models.IntegerField()


class Failures(models.Model):
    FAILURE_CHOICES = (
    ('SC', 'Screen'),
    ('BA', 'Battery'),
    ('BX', 'Box'),
    # etc, with 10+ choices
    )

    name = models.CharField(max_length=2, choices=FAILURE_CHOICES)


class Market(models.Model):
    MARKET_CHOICES = (
    ('ED', 'Education'),
    ('CO', 'Commercial'),
    # etc, with 10 choices
    )

    product = models.ForeignKey(Product)
    market = models.CharField(max_length=2,choices=MARKET_CHOICES)
    failures = models.ManyToManyField(Failures, blank=True)

我有这样一个观点：

fails = ['SC','BA','BX',etc]

markets = [['ED'],['CO'],etc]

def fail_counter(fails):
    dictlist=[]
    for failure in fails:
    # dict1 = {failure:count}
        c = Failures(name=failure)
        d = str(c.get_name_display())
        kwargs = {d: (Count('failures'))}
        dict1 = total.filter(market__in=mark, failures__name=failure).aggregate(**kwargs)
        dictlist.append(dict1)
    return(dictlist)

fail_list=[]
for mark in markets:
    fail_list.append(fail_counter(fails))

然后将fail_列表传递给模板，模板将其解压到表中， 所以我得到了乙二醇

Market1(education)   Market2(commercial)    Market3(etc)
Failure   Count      Failure   Count        Failure   Count
Screen    0          Screen    0            Screen    0
Battery   0          Battery   1            Battery   0
Box       1          Box       0            Box       0
etc

将任何计数>0转换为指向管理员之类的链接的最佳方法是什么

---

该计数中特定产品代码的更改列表？

在模板中，您可以使用密码，是否尝试测试

if value>0

。或者你到底需要什么？如果计数大于0，我需要得到实际的查询集。目前，我只是将计数发送到此模板。我可以将queryset和count都放在上下文中（似乎太多了），但是如何将queryset从这个模板发送到另一个模板（如果count>0）？