从java运行Linux命令
我正在尝试从java运行一个命令。但命令并没有执行。有人能指出原因吗从java运行Linux命令,java,linux,Java,Linux,我正在尝试从java运行一个命令。但命令并没有执行。有人能指出原因吗 String path = dest+"/info_updated.csv"; File file = new File(path); String command = "sed -i '/" + subscriberId + "/d' "+file; System.out.println("command "+command); Runtime run = Runtime.getR
String path = dest+"/info_updated.csv";
File file = new File(path);
String command = "sed -i '/" + subscriberId + "/d' "+file;
System.out.println("command "+command);
Runtime run = Runtime.getRuntime();
Process p = null;
try {
p = run.exec(command);
InputStream errorStream = p.getErrorStream();
p.waitFor();
} catch (IOException ioe) {
ioe.printStackTrace();
System.out.println("ERROR.RUNNING.CMD");
} catch (Exception e) {
e.printStackTrace();
} finally {
p.destroy();
}
return true;
}
在日志中,它正在正确打印命令
command sed -i '/L13876110226750000/d' /usr/share/apache-tomcat-6.0.37/webapps/SMS/info_updated.csv
但是它没有执行。您可以在命令之前添加
/bin/sh-c
,然后再试一次
像这样:
String[] command = {"/bin/sh", "-c", "sed -i '/" + subscriberId + "/d' "+file};
Process p = run.exec(command);
-e
代替或补充-i
?定义“不执行”,任何堆栈跟踪?此外,这很可能会使tomcat重新部署SMS webappNo shell=>no quoting。