在java中生成随机静态最终数

我正在为我的学校做一个游戏，我不能让一个静态的最终整数得到一个随机数，游戏是小行星，小行星是用多边形制作的，我可以用这个来改变多边形的点：

private static final int NUMBER_OF_POINTS = 5;

如果我把

private static final int NUMBER_OF_POINTS = 3;

它形成了一个三角形，但我希望当游戏开始时，它会通过在下列区域中生成随机数来生成随机数字：

private static final int NUMBER_OF_POINTS = 3;

以下是我制作的，但不起作用：

private static final int NUMBER_OF_POINTS = 3 + (int)(Math.random() * (5 - 3) + 1));

下面是全部代码：

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package game;

import java.awt.Polygon;
import java.util.Random;


public enum AsteroidSize {

    /**
     * Small Asteroids have a radius of 15, and are worth 150 points.
     */
    XtraSmall(5.0, 150),
    /**
     * Small Asteroids have a radius of 15, and are worth 100 points.
     */
    Small(15.0, 100),

    /**
     * Medium asteroids have a radius of 25, and are worth 50 points.
     */
    Medium(25.0, 50),

    /**
     * Large asteroids have a radius of 40, and are worth 20 points.
     */
    Large(40.0, 20),
        /**
     * XtraLarge asteroids have a radius of 40, and are worth 10 points.
     */
        XtraLarge(50.0, 10);

    /**
     * The number of points on the Asteroid.
     */
    private static final int NUMBER_OF_POINTS = 5;

    /**
     * The polygon for this type of Asteroid.
     */
    public final Polygon polygon;

    /**
     * The radius of this type of Asteroid.
     */
    public final double radius;

    /**
     * The number of points earned for killing this type of Asteroid.
     */
    public final int killValue;

    /**
     * Creates a new type of Asteroid.
     * @param radius The radius.
     * @param value The kill value.
     */
    private AsteroidSize(double radius, int value) {
        this.polygon = generatePolygon(radius);
        this.radius = radius + 1.0;
        this.killValue = value;
    }

    /**
     * Generates a regular polygon of size radius.
     * @param radius The radius of the Polygon.
     * @return The generated Polygon.
     */
    private static Polygon generatePolygon(double radius) {
        //Create an array to store the coordinates.
        int[] x = new int[NUMBER_OF_POINTS];
        int[] y = new int[NUMBER_OF_POINTS];

        //Generate the points in the polygon.
        double angle = (2 * Math.PI / NUMBER_OF_POINTS);
        for(int i = 0; i < NUMBER_OF_POINTS; i++) {
            x[i] = (int) (radius * Math.sin(i * angle));
            y[i] = (int) (radius * Math.cos(i * angle));
        }

        //Create a new polygon from the generated points and return it.
        return new Polygon(x, y, NUMBER_OF_POINTS);
    }

}

试试这个

Random random = new Random();
int rand;
rand = random.nextInt(8) + 3; // here a number will be generated between 3 and 8, 3 is a triangle 8 octogon so you can change 8 but leave 3 alone.
NUMBER_OF_POINTS = rand; // number of points is now equal to a number between 3 and 8.

---

我有一种感觉，你不能改变一个最终变量的值，所以也许可以去掉最终变量。让我知道这是否符合您的要求。

Define不起作用。你预计会发生什么，会发生什么？我预计生成的小行星有不同的形状，比如如果我放3个点，我会看到一个三角形，如果我放4个点，我会看到一个矩形，相反，它不会显示数字，如果我开始拍摄，我会因为碰撞而得到点，但数字不会出现，所以它与随机静态最终int无关？你在问为什么数字没有出现在屏幕上？嗯，你没有发布任何与在屏幕上显示数字相关的代码，因此很难帮助。你也可以通过改变每边的长度来增加半径。这对我来说是有效的，是的，最终是所有的问题，汤姆我没有想到这一点