具有十六进制长数组数据类型java的CRC16

我正试图通过使用以下代码获得正确的CRC16

 public static int GenCrc16(final byte[] buffer) {
    int crc = 0xffff;
    for (int j = 0; j < buffer.length ; j++) {
    crc = ((crc  >>> 8) | (crc  << 8) )& 0xffff;
    crc ^= (buffer[j] & 0xff);//byte to int, trunc sign
    crc ^= ((crc & 0xff) >> 4);
    crc ^= (crc << 12) & 0xffff;
    crc ^= ((crc & 0xFF) << 5) & 0xffff;
    }
    crc &= 0xffff;
    return crc;
    }

我得到了0x17B5，这是正确的，但我希望将数据作为 作为原始数据

long[] inputLongArray= {0x00000140, 0x00000000, 0x00000002, 0x00000001}
public static byte[] toByte(long[] longArray) {
ByteBuffer bb = ByteBuffer.allocate(longArray.length * Long.BYTES);
bb.asLongBuffer().put(longArray);
return bb.array();
}

我期待0x1F19，如下所示 00000140 00000000 00000002 00000001并选择十六进制数据类型和CRC-16/CCITT-FALSE

public static void main(String[] args) {

long[] intputarray = {0x00000140, 0x0000000, 0x000000002, 0x0000001};      

System.out.println(Integer.toHexString(GenCrc16(toByte(intputarray)));
}

---

我做错了什么。提前谢谢你的帮助

long

值是8个字节，也就是16个十六进制数字，所以

long[]{0x00000140，0x00000000，0x00000002，0x00000001}

与

“000000000000014000000000000000000000000000000000000000000020000000000000001”

并且都具有CRC-16/CCITT-FALSE值

---

字符串

“000001400000000000000020000001”

应该是

“0000014000000000000002000000001”

这与

int[]{0x00000140，0x00000000，0x00000002，0x00000001}

并且都具有CRC-16/CCITT-FALSE值

public static void main(String[] args) {

long[] intputarray = {0x00000140, 0x0000000, 0x000000002, 0x0000001};      

System.out.println(Integer.toHexString(GenCrc16(toByte(intputarray)));
}

public static byte[] toByte(final int... intArray) {
    ByteBuffer bb = ByteBuffer.allocate(intArray.length * Integer.BYTES);
    bb.asIntBuffer().put(intArray);
    return bb.array();
}