使用java解析和排序JSON数据

我希望使用org.json.simple库解析以下数组，但遇到了一些困难。有人能看看我的json文件和代码，告诉我哪里做错了吗

{
  "Company": [
{
  "Department": "Engineering",
  "Employee": [
    {
      "EmpName": "Jack",
      "EmpCode": "8",
      "Type": "Permanent"
    }, {
      "EmpName": "John",
      "EmpCode": "45",
      "Type": "Permanent"
    }, {
      "EmpName": "Ron",
      "EmpCode": "9",
      "Type": "Contract"
    }, {
      "EmpName": "Jin",
      "EmpCode": "6",
      "Type": "Permanent"
    }, {
      "EmpName": "Jill",
      "EmpCode": "",
      "Type": "Retired"
    }, {
      "EmpName": "Sam",
      "EmpCode": "89",
      "Type": "Permanent"
    }, {
      "EmpName": "Jonathan",
      "EmpCode": "66",
      "Type": "Permanent"
    }, {
      "EmpName": "Craig",
      "EmpCode": "",
      "Type": "Ex-Employee"
    }, {
      "EmpName": "Son Hui",
      "EmpCode": "4",
      "Type": "Permanent"
    }, {
      "EmpName": "Joshua",
      "EmpCode": "12",
      "Type": "Contract"
    }, {
      "EmpName": "Tulip",
      "EmpCode": "70",
      "Type": "Contract"
    }
  ]
}, {
  "Department": "IT",
  "Employee": [
    {
      "EmpName": "Nico",
      "EmpCode": "50",
      "Type": "Resigned"
    }, {
      "EmpName": "Phil",
      "EmpCode": "103",
      "Type": "Resigned"
    }
  ]
}
  ]
}

请注意，一些EmpCode字段也是空白的。我该如何处理它们。此外，我需要能够在显示数据时重新排列数据，我的意思是我需要根据EmpCode或类型对数据进行排序

我为解析上述json而编写的代码如下所述：

package amazontesting;

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

import java.io.FileNotFoundException;
import java.io.FileReader;

import java.io.IOException;
import java.util.Iterator;

public class json {
    private static final String filePath = /emp.json";
    public static void main(String[] args) {
        JSONParser parser = new JSONParser();
        try {
        Object obj = parser.parse(new FileReader(filePath));
        JSONObject jsonObject = (JSONObject) obj;
        String name = (String) jsonObject.get("Department");
        //String suites = (String) jsonObject.get("Company");


        JSONArray slideContent = (JSONArray) jsonObject.get("Department");
        Iterator i = slideContent.iterator();

        while (i.hasNext()) {
            System.out.println(i.next());
            String title = (String) jsonObject.get("Employee");
            System.out.println(title);
        }
    }
    catch (FileNotFoundException e)
    {}
    catch(IOException e)
    {}
    catch(ParseException e)
    {}

    }
}

---

看起来您对Json结构的工作原理以及它可能包含的对象类型有误解

例如，您认为您在这段代码中做了什么

JSONArray slideContent = (JSONArray) jsonObject.get("Department");
Iterator i = slideContent.iterator();

看起来您试图获取名为“Department”的json对象，但它不是JsonArray，而是字符串

"Department": "Engineering"
//Writing code "jsonObject.get("Department")" 
//you will get string "Engineering"

//this code will be correct
(JSONArray) jsonObject.get("Employee")
//because a json value for name "Employee" it's an JsonArray

---

“告诉我做错了什么”不是一个合适的问题。请准确描述您遇到了什么问题，您做了什么来诊断问题，然后构造一个。此外，代码中引用的JSON听起来不像发布的JSON。@OliverCharlesworth抱歉，关于错误的JSON引用，我现在已经更新了。我是处理JSON的新手，所以我在互联网上阅读并尝试使用示例代码。有些帖子提到我应该创建一个基于json的类，然后在主类中调用它，而有些帖子提到上面的代码就可以做到这一点。我尝试运行此代码，department打印空。我假设这会创建一个包含department下所有员工的数组。它将为名称“department”获取值，该值为字符串“Engineering”，感谢您提供的信息。我想我会多读一点这方面的内容