Java 如何更改特定属性的JsonView
嗨,我有几个相互嵌入的UI对象。示例#1: 正如您所看到的,如果我将UserUI序列化为Public,我将只公开name,但对于private,我将公开所有字段 这里是我的问题:当我序列化对象CarUI时,我只想为“user”公开名称,为“agent”公开名称+电话。这本质上意味着在getUser()的getter中,我想将JsonView更改为Views.Public.class,而对于getAgent()我想将其更改为Views.Private.class 有没有办法覆盖getter中的JsonView,使返回对象的所有层次结构现在都使用这个新的JsonView序列化 已编辑 正如下面指出的,您可以使用JsonView继承解决我的示例#1。更一般的呢。以下是示例#2:Java 如何更改特定属性的JsonView,java,serialization,jackson,json-view,Java,Serialization,Jackson,Json View,嗨,我有几个相互嵌入的UI对象。示例#1: 正如您所看到的,如果我将UserUI序列化为Public,我将只公开name,但对于private,我将公开所有字段 这里是我的问题:当我序列化对象CarUI时,我只想为“user”公开名称,为“agent”公开名称+电话。这本质上意味着在getUser()的getter中,我想将JsonView更改为Views.Public.class,而对于getAgent()我想将其更改为Views.Private.class 有没有办法覆盖getter中的Js
在本例中,Id希望为代理显示name+phone,为用户显示name+avatarUrl。@JsonView接受继承。视图。专用字段扩展视图。公用字段。这意味着视图。私有序列化也将查找视图。公共注释
public Views {
public Public {}
public Private extends Public {}
}
class CarUI {
public UserUI user;
public UserUI agent;
....
@JsonView(Views.Public.class)
public UserUI getUser() {
return user;
}
@JsonView(Views.Private.class)
public UserUI getAgent() {
return agent;
}
}
class UserUI {
@JsonView(Views.Public.class)
public String name;
@JsonView(Views.Private.class)
public String phone;
...
}
例如#2
您可以引入多个类,如:
public Views {
public Public {}
public Private1 extends Public {}
public Private2 extends Public {}
}
class CarUI {
public UserUI user;
public UserUI agent;
....
public UserUI getUser() {
return user;
}
public UserUI getAgent() {
return agent;
}
}
class UserUI {
@JsonView(Views.Public.class)
public String name;
@JsonView({Views.Private1.class})
public String phone;
@JsonView({Views.Private2.class})
public String avatarUrl;
...
}
或者,您可以使用无视图属性且不使用继承:
public Views {
public Public {}
public Private {}
}
class CarUI {
public UserUI user;
public UserUI agent;
....
public UserUI getUser() {
return user;
}
public UserUI getAgent() {
return agent;
}
}
class UserUI {
// This one is view-less shows every time unless you specificy
public String name;
@JsonView({Views.Private.class})
public String phone;
@JsonView({Views.Public.class})
public String avatarUrl;
...
}
...
// If you want to hide view-less properties, default is true
objectMapper.configure(SerializationConfig.Feature.DEFAULT_VIEW_INCLUSION, false);
...
如果有人需要的话,可以找到更通用的案例。基本上,您可以使用不同的JsonView在getter内部转换属性,如下所示:
@JsonView({ Views.Detail.class})
public JsonNode getAgent() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String json = mapper.writerWithView(Views. Private.class).writeValueAsString(agent);
return mapper.readTree(json);
}
非常感谢。这将适用于我的示例,其中两个JSONView在属性上重叠。如果公共部门拥有私人部门所没有的财产,而私人部门拥有相反的财产,该怎么办。参见上面的例子#2.编辑我的答案。试图在@JsonView注释中使用多个类,但没有成功。
public Views {
public Public {}
public Private {}
}
class CarUI {
public UserUI user;
public UserUI agent;
....
public UserUI getUser() {
return user;
}
public UserUI getAgent() {
return agent;
}
}
class UserUI {
// This one is view-less shows every time unless you specificy
public String name;
@JsonView({Views.Private.class})
public String phone;
@JsonView({Views.Public.class})
public String avatarUrl;
...
}
...
// If you want to hide view-less properties, default is true
objectMapper.configure(SerializationConfig.Feature.DEFAULT_VIEW_INCLUSION, false);
...
@JsonView({ Views.Detail.class})
public JsonNode getAgent() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String json = mapper.writerWithView(Views. Private.class).writeValueAsString(agent);
return mapper.readTree(json);
}