Java 字符串子字符串错误

Java 字符串子字符串错误,java,string,Java,String,问题: Input:-gandhi output:- Gandhi Input:-mahatma gandhi output:- M. Gandhi Input:-Mohndas Karamchand ganDhi output:- M. K. Gandhi 答复: public class Chef_NITIKA { static Scanner scan=new Scanner(System.in);

问题:

Input:-gandhi                      output:- Gandhi
Input:-mahatma gandhi              output:- M. Gandhi 
Input:-Mohndas Karamchand ganDhi   output:- M. K. Gandhi
答复:

public class Chef_NITIKA {

    static Scanner scan=new Scanner(System.in);

    public static void main(String[] args) {
        String name=    myString();
        System.out.println("nam is :"+name);
        mySformatter(name);

    }

    private static void mySformatter(String name) {
           int count=0;
          for(char c:name.toCharArray()){
              if(c==' '){
                  count+=1;
              }
          }
          System.out.println(count+" blank spaces");
          if(count==0){
              char ch=name.charAt(0);
              name=Character.toUpperCase(ch)+name.substring(1);
              System.out.println("nam is :"+name);
          }
          else if(count==1){
              char ch=name.charAt(0);
             name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(".")+1);
             char c=subname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name=Character.toUpperCase(ch)+"."+subname;
              System.out.println("nam is :"+name);
          }
          else if(count==2){
              char ch=name.charAt(0);
            // name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(" ")+1);
             System.out.println(subname);
             String subsubname=subname.substring(name.indexOf(" "));
             System.out.println(subsubname);
             char c=subname.charAt(0);
             char c1=subsubname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name = Character.toUpperCase(ch)+"."+Character.toUpperCase(c)+"."+Character.toUpperCase(c1)+subsubname.substring(1);
              System.out.println("nam is :"+name);
          }
    }

    private static String myString() {
       System.out.println("enter the string");
       String s=scan.nextLine();
       StringBuffer name=new StringBuffer();
     //  name.append(s);
       return s;
    }
}
当我输入“abc cde fgh”时,我没有得到所需的输出,我得到的输出是A.C..fgh

有什么有效的方法来解决这个问题吗

不期望的输出:-

enter the string
iam writing onStack
nam is :iam writing onStack
2 blank spaces
writing onStack
ing onStack
nam is :I.W.Ing onStack

我希望输出为I.W.OnStack

只需将名称拆分为组件,然后形成所需的缩写:

public static String getName(String input) {
    String[] names = input.split("\\s+");
    String output = "";

    // replace 1st through second to last names with capitalized 1st letter
    for (int i=names.length; i > 1; --i) {
        output += names[names.length - i].substring(0, 1).toUpperCase() + ". ";
    }

    // append full last name, first letter capitalized, rest lower case
    output += names[names.length - 1].substring(0, 1).toUpperCase()
           + names[names.length - 1].substring(1).toLowerCase();

    return output;
}

public static void main(String[] args) {
    System.out.println(getName("gandhi"));
    System.out.println(getName("mahatma gandhi"));
    System.out.println(getName("Mohndas Karamchand ganDhi"));
}
输出:

Gandhi
M. Gandhi
M. K. Gandhi
此处演示:

Gandhi
M. Gandhi
M. K. Gandhi

更新:

Gandhi
M. Gandhi
M. K. Gandhi
下面是一个例子,我已经纠正了您的原始代码,至少部分是这样。问题如下:

String subsubname = subname.substring(name.indexOf(" "));
我将其改为:

String subsubname = subname.substring(subname.indexOf(" ") + 1);

您没有正确识别名称第三部分的第一个字符。话虽如此,您当前的方法冗长、难以理解且缺乏灵活性。实际上,您可能希望使用更精简的方法来解决此问题。

只需将名称拆分为组件,然后形成所需的缩写:

public static String getName(String input) {
    String[] names = input.split("\\s+");
    String output = "";

    // replace 1st through second to last names with capitalized 1st letter
    for (int i=names.length; i > 1; --i) {
        output += names[names.length - i].substring(0, 1).toUpperCase() + ". ";
    }

    // append full last name, first letter capitalized, rest lower case
    output += names[names.length - 1].substring(0, 1).toUpperCase()
           + names[names.length - 1].substring(1).toLowerCase();

    return output;
}

public static void main(String[] args) {
    System.out.println(getName("gandhi"));
    System.out.println(getName("mahatma gandhi"));
    System.out.println(getName("Mohndas Karamchand ganDhi"));
}
/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package stack;

import java.util.Scanner;
import java.util.StringTokenizer;

/**
 *
 * @author xxz
 */
public class NAmes {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        final String name = sc.nextLine();
        System.out.println(formatedString(name));
        sc.close();
    }

    private static String formatedString(String name) {
        if(name!=null && name.length()!=0){
            final StringTokenizer tokenizer = new StringTokenizer(name, " ");
            StringBuilder result = new StringBuilder("");
              while(tokenizer.hasMoreTokens()){
                StringBuilder currentToken =new StringBuilder(tokenizer.nextToken());

                if(!tokenizer.hasMoreTokens()){
                    result.append(currentToken.toString().toUpperCase());
                } else{
                    result.append(currentToken.toString().toUpperCase().charAt(0)+". ");
                }
            }
            return result.toString();
        }
        return "";
    }
}
输出:

Gandhi
M. Gandhi
M. K. Gandhi
此处演示:

Gandhi
M. Gandhi
M. K. Gandhi

更新:

Gandhi
M. Gandhi
M. K. Gandhi
下面是一个例子,我已经纠正了您的原始代码,至少部分是这样。问题如下:

String subsubname = subname.substring(name.indexOf(" "));
我将其改为:

String subsubname = subname.substring(subname.indexOf(" ") + 1);
您没有正确识别名称第三部分的第一个字符。话虽如此,您当前的方法冗长、难以理解且缺乏灵活性。实际上,您可能希望使用更精简的方法来解决此问题。

@Rushabh Oswal您可以通过以下方法获得所需的结果
/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package stack;

import java.util.Scanner;
import java.util.StringTokenizer;

/**
 *
 * @author xxz
 */
public class NAmes {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        final String name = sc.nextLine();
        System.out.println(formatedString(name));
        sc.close();
    }

    private static String formatedString(String name) {
        if(name!=null && name.length()!=0){
            final StringTokenizer tokenizer = new StringTokenizer(name, " ");
            StringBuilder result = new StringBuilder("");
              while(tokenizer.hasMoreTokens()){
                StringBuilder currentToken =new StringBuilder(tokenizer.nextToken());

                if(!tokenizer.hasMoreTokens()){
                    result.append(currentToken.toString().toUpperCase());
                } else{
                    result.append(currentToken.toString().toUpperCase().charAt(0)+". ");
                }
            }
            return result.toString();
        }
        return "";
    }
}
私有静态void mySformatter(字符串名称){ 字符串[]tempArray=name.split(“”); StringBuilder outputStr=新建StringBuilder(); int len=tempArray.length; 对于(inti=0;i
@Rushabh Oswal),您可以通过以下方法获得所需的结果
私有静态void mySformatter(字符串名称){
字符串[]tempArray=name.split(“”);
StringBuilder outputStr=新建StringBuilder();
int len=tempArray.length;

对于(int i=0;i“abc cde fgh”的期望输出是什么?“abc cde fgh”的期望输出是什么?我编译了你的代码并得到了正确的输出,但是你能在我的代码中找到错误吗?主要是当计数为2ya时,我已经发布了我的输出getting@RushabhOswal我现在正在测试您的代码,请给我几分钟时间。在ny second演示中,我能够获得
abc cde fgh
的正确输出。正如我所说,您当前的方法是不理想,所以我不会花更多时间调试它。我编译了你的代码并得到了正确的输出,但是你能在我的代码中找到错误吗?主要是当计数为2ya时,我已经发布了我的输出getting@RushabhOswal我现在正在测试您的代码,请给我几分钟时间。在第二次演示中,我能够获得
abc cde的正确输出fgh
。正如我所说,您当前的方法并不理想,因此我不会花更多时间调试它。我想知道当计数器==2时,代码中的错误是什么。我想知道当计数器==2时,代码中的错误是什么