Javascript 有角度的2个空动画Don';不要在移动时开火
如何在Angular2中删除dom元素时启动动画Javascript 有角度的2个空动画Don';不要在移动时开火,javascript,angular,animation,angular2-animation,Javascript,Angular,Animation,Angular2 Animation,如何在Angular2中删除dom元素时启动动画 import { Component, Input, Output, EventEmitter } from '@angular/core'; import { FormGroup, FormControl, Validators } from "@angular/forms"; import { trigger, state, style, animate, transition } from '@angular/anim
import { Component, Input, Output, EventEmitter } from '@angular/core';
import { FormGroup, FormControl, Validators } from "@angular/forms";
import {
trigger,
state,
style,
animate,
transition
} from '@angular/animations';
import { ServerService } from './server.service';
@Component({
selector: 'fc-server',
templateUrl: './server.component.html',
animations: [
trigger('flyInFlyOut', [
state('*', style({transform: 'translateX(0)', opacity: 1})),
transition('void => *', [
style({transform: 'translateX(-100%)', opacity: 0}),
animate('400ms ease')
]),
transition('* => void', [
style({transform: 'translateX(-100%)'}),
animate('400ms ease')
])
])
]
})
export class Server {
@Input() serverInstance;
serverForm;
constructor(
private serverService: ServerService) {}
ngOnInit() {
this.serverForm = new FormGroup({
serverName: new FormControl('', Validators.required),
serverPort: new FormControl('', Validators.required),
serverIp: new FormControl('', Validators.required),
});
}
@Output() remove = new EventEmitter();
onRemove() {
this.serverService.remove(this.serverInstance);
}
onSubmit(serverInstance) {
this.serverService.add(serverInstance);
}
}
一切正常,从列表中删除项目,向列表中添加项目,在…中添加动画,除非删除项目,否则将删除列表项目而不添加动画。有什么见解吗
这似乎是安格拉尔再次出现的问题,但就我所见,没有人真的有一个好的解决方案
例如,本文:您还需要定义
void
的结束状态
:
state('void',style({transform:'translateX(100%),不透明度:0}))
然后删除样式({transform:'translateX(-100%)}),
行在*=>void
转换中
或者我会用我认为更容易理解的形式来写:
trigger('flyInFlyOut', [
transition(':enter', [
// the element receives this style immediately and then animates to the
// next style which is the `style({ transform: 'translateX(0)', opacity: 1 })`
style({ transform: 'translateX(-100%)', opacity: 0 }),
animate('300ms', style({ transform: 'translateX(0)', opacity: 1 })),
]),
transition(':leave', [
style({ transform: 'translateX(0)', opacity: 1 }),
animate('200ms', style({ transform: 'translateX(100%)', opacity: 0 })),
]),
]);
:leave
和:enter
分别是*=>void
和void=>*
的缩写。我不知道您是否仍然需要解决方案,但您可以将动画设置为host为true,对于更干净的代码,您可以定义void state和not*(默认)的样式,angular足够聪明,可以知道最终样式应该是什么样子,例如:
@Component({
selector: 'fc-server',
templateUrl: './server.component.html',
animations: [
trigger('flyInFlyOut', [
state('void', style({transform: 'translateX(-100%)', opacity: 0})),
transition('void => *', [
animate('400ms ease')
]),
transition('* => void', [
animate('400ms ease')
])
])
],
host: {
'[@flyInFlyOut]': 'true'
}
})
另外,如果您想为(void=>)和(=>void)转换使用别名,它们分别是(:enter)和(:leave),如另一个答案中所述
我遇到了完全相同的问题,并且找到了这个解决方案。希望有帮助。:) 看起来原版应该有效(在文档中):我试过你的例子,行为是不变的