Javascript 使用回调更改bokeh中的绘图源
假设我有两个(或更多)具有相同列数和行数的数据源:Javascript 使用回调更改bokeh中的绘图源,javascript,python,bokeh,Javascript,Python,Bokeh,假设我有两个(或更多)具有相同列数和行数的数据源: #Data dates = [date(2016, i, 1) for i in range(1,13)] data1 = pd.DataFrame(index = dates, data = random.randn(12, 2), columns = ['A', 'B']) data2 = pd.DataFrame(index = dates, data = random.randn(12, 2
#Data
dates = [date(2016, i, 1) for i in range(1,13)]
data1 = pd.DataFrame(index = dates, data = random.randn(12, 2),
columns = ['A', 'B'])
data2 = pd.DataFrame(index = dates, data = random.randn(12, 2),
columns = ['A', 'B'])
我想在bokeh绘制A列和B列,如下所示:
#Bokeh
source = ColumnDataSource(source1)
source1 = ColumnDataSource(data1)
source2 = ColumnDataSource(data2)
p = figure(x_axis_type = 'datetime')
l1 = p.line(source = source, x = dates, y= 'A', color = 'Red')
l2 = p.line(source = source, x = dates, y= 'B', color = 'Blue')
我有一个下拉列表:
select = Select(options = ['source1', 'source2'], value = 'source1')
为select
创建回调以便在下拉列表中选择不同选项时更改折线图中的数据源的最简单方法是什么?我在JS方面几乎没有经验,也无法真正理解回调,因此任何帮助都将不胜感激
编辑:
我试过这个:
codes = """
var f = cb_obj.get('value');
var sdata = source.data;
var 1data = source1.data;
var 2data = source2.data;
if (f == "source1") {
sdata = 1data ;
source.trigger('change');
};
if (f == "source2") {
sdata = 2data ;
source.trigger('change');
};
"""
select.callback= CustomJS(args= dict(source = source, source1=source1,
source2=source2), code = codes)
但它不起作用…编辑:
obj.trigger('change',arg)
已针对bokeh 0.12.6进行了更改,现已弃用,新语法为obj.change.emit(arg)
,请参阅
您可以清空“源”数据列,并使用.push()在for循环中重新填充它们
此外,不应使用以数字开头的变量名
codes = """
var f = cb_obj.get('value');
var sdata = source.data;
var data1 = source1.data;
var data2 = source2.data;
if (f == "source1") {
sdata["A"] = [] ;
for (i=0;i<data1["A"].length; i++) {
sdata["A"].push(data1["A"][i]);
}
sdata["B"] = [] ;
for (i=0;i<data1["B"].length; i++) {
sdata["B"].push(data1["B"][i]);
}
source.trigger('change');
};
if (f == "source2") {
sdata["A"] = [] ;
for (i=0;i<data2["A"].length; i++) {
sdata["A"].push(data2["A"][i]);
}
sdata["B"] = [] ;
for (i=0;i<data2["B"].length; i++) {
sdata["B"].push(data2["B"][i]);
}
source.trigger('change');
};
"""
code=”“”
var f=cb_obj.get('value');
var sdata=source.data;
var data1=source1.data;
var data2=source2.data;
如果(f==“源1”){
sdata[“A”]=[];
对于(i=0;iThank you@Seb,这很好用。我的实际数据源有10多列,你能想出任何方法来简化代码吗?还是必须一列一列地进行?谢谢,阿加尼假设每列有一行,你可以循环字典键,我用一个示例codePerfect编辑了我的答案。谢谢ch@SebPlease update:source.trigger(“change”)
已去除润滑。请改用source.change.emit()
。
from bokeh.plotting import figure, output_file
from bokeh.models import CustomJS, ColumnDataSource, Select
from bokeh.layouts import gridplot
from bokeh.resources import CDN
from bokeh.embed import file_html
from random import random
key_list = list('ABCDEFGHIJKLMNOP')
DATA1 = {key:[random() for i in range(10)] for key in key_list}
DATA2 = {key:[random() for i in range(10)] for key in key_list}
DATA1['xaxis'] = range(10)
DATA2['xaxis'] = range(10)
source1 = ColumnDataSource(data=DATA1)
source2 = ColumnDataSource(data=DATA2)
fill_source = ColumnDataSource(data=DATA1)
fig = figure()
for key in key_list:
fig.line(x='xaxis',y=key,source=fill_source)
select = Select(options=['source1','source2'],value='source1')
codes = """
var f = cb_obj.value;
var sdata = source.data;
var data1 = source1.data;
var data2 = source2.data;
console.log(data2);
for (key in data1) {console.log(key);}
if (f == "source1") {
for (key in data1) {
sdata[key] = [];
for (i=0;i<data1[key].length;i++){
sdata[key].push(data1[key][i]);
}
}
} else {
for (key in data2) {
sdata[key] = [];
for (i=0;i<data2[key].length;i++){
sdata[key].push(data2[key][i]);
}
}
};
source.trigger("change");
"""
select.callback = CustomJS(args=dict(source=fill_source,source1=source1,source2=source2),code=codes)
grid = gridplot([[select],[fig]])
outfile=open('select.html','w')
outfile.write(file_html(grid,CDN,'select'))
outfile.close()